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JMET 2007 Paper with answers

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x = X – (2.5 + 0.5 + 1.0) = 8.7 – 4.0 = 4.7<br />

y = Y – (2.5 + 0.5 + 1.5) = 9.1 – 4.5 = 4.6<br />

z = Z – (1.0 + 0.5 + 1.5) = 5.6 – 3.0 = 2.6<br />

Q.13 The number of people (in lakhs) who read at least one newspaper is<br />

(A) 4.7 (B) 11.9 (C) 17.4 (D) 23.4<br />

Solution 13. Number of people reading at least one newspaper = 4.7 + 2.6 + 4.6 + 5.5 = 17.4<br />

Hence, answer is (C)<br />

Q.14 The number of people (in lakhs) who read only one newspaper is<br />

(A) 4.7 (B) 11.9 (C) 17.4 (D) 23.4<br />

Solution 14. Number of people reading only one newspaper = 4.7 + 4.6 + 2.6 = 11.9<br />

Hence, answer is (B)<br />

Q.15 The approximate percentage of population reading at least two newspapers is<br />

(A) 2.9 (B) 3.5 (C) 3.9 (D) None of the above<br />

Solution 15. Population reading at least two newspapers = 2.5 + 1.0 + 1.5 + 0.5 = 5.5 lakhs<br />

Total population of city = 14 million = 140 lakh<br />

Percentage of these readers, of total population = (5.5 / 140) * 100 = 3.928 %<br />

Hence, answer is (C)<br />

Q.16 The combination of any two newspapers that gives the minimum advertising cost (in Rs.<br />

per sq. cm.) per 1000 readers is<br />

(A) X and Y (B) Y and Z (C) X and Z (D) None of the above<br />

Solution 16.<br />

Combined Total Reader of two Advertising Cost<br />

Advertising Cost newspaper (in lakhs) per 1000 readers<br />

X and Y 12500 14.8 844.59<br />

Y and Z 11500 12.7 905.512<br />

Z and X 11000 12.8 859.375

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