1.3 Handout on Trig Identities - Kkuniyuk.com
1.3 Handout on Trig Identities - Kkuniyuk.com
1.3 Handout on Trig Identities - Kkuniyuk.com
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SUM IDENTITIES<br />
MATH 150: MORE TRIG IDENTITIES - KNOW THESE!<br />
(SECTION <str<strong>on</strong>g>1.3</str<strong>on</strong>g>, pp. 36-37; back endpapers)<br />
Memorize:<br />
( ) = +<br />
sin u + v sinucosv cosusinv<br />
Think: “Sum of the mixed-up products”<br />
(Multiplicati<strong>on</strong> and additi<strong>on</strong> are <strong>com</strong>mutative, but start with the<br />
sinucosv term in anticipati<strong>on</strong> of the Difference <strong>Identities</strong>.)<br />
( ) = -<br />
cos u + v cosucosv sinusinv<br />
tan ( u + v) =<br />
DIFFERENCE IDENTITIES<br />
Memorize:<br />
Think: “Cosines [product] – Sines [product]”<br />
tanu<br />
+ tanv<br />
1 - tanutanv<br />
Sum<br />
Think: " "<br />
1 - Product<br />
Simply take the Sum <strong>Identities</strong> above and change every sign in sight!<br />
( ) = -<br />
sin u - v sinucosv cosusinv<br />
( Make sure that the right side of your identity<br />
for sin u + v started with the sinucosv<br />
term!)<br />
( )<br />
( ) = +<br />
cos u - v cosucosv sinusinv<br />
tan ( u - v) =<br />
tanu<br />
- tanv<br />
1 + tanutanv<br />
Obtaining the Difference <strong>Identities</strong> from the Sum <strong>Identities</strong>:<br />
Replace v with (–v) and use the fact that sin and tan are odd, while cos is even.<br />
For example,<br />
sin<br />
[ ]<br />
( ) = + (-<br />
)<br />
u - v sin u v<br />
= sinucos (-v) + cosusin<br />
-v<br />
= sinucosv -cosusinv<br />
( )
DOUBLE-ANGLE (Think: Angle-Reducing, if u > 0) IDENTITIES<br />
Memorize:<br />
(Also be prepared to recognize and know these “right-to-left”)<br />
( ) =<br />
sin 2u 2sinucosu<br />
Think: “Twice the product”<br />
Reading “right-to-left,” we have:<br />
2sinucosu sin 2u<br />
= ( )<br />
(This is helpful when simplifying.)<br />
( ) = -<br />
2 2<br />
cos 2u cos u sin u<br />
Think: “Cosines – Sines” (again)<br />
Reading “right-to-left,” we have:<br />
2 2<br />
cos u sin u cos 2u<br />
- = ( )<br />
C<strong>on</strong>trast this with the Pythagorean Identity:<br />
cos<br />
u + sin u = 1<br />
2 2<br />
2 tanu<br />
tan ( 2u) =<br />
2<br />
1 - tan u<br />
(Hard to memorize; we’ll show how to obtain it.)<br />
Notice that these identities are “angle-reducing” (if u > 0) in that they allow you<br />
to go from trig functi<strong>on</strong>s of (2u) to trig functi<strong>on</strong>s of simply u.
Obtaining the Double-Angle <strong>Identities</strong> from the Sum <strong>Identities</strong>:<br />
Take the Sum <strong>Identities</strong>, replace v with u, and simplify.<br />
sin<br />
( 2u) = sin ( u + u)<br />
= sinucosu + cosusinu<br />
= sinucosu + sinucosu<br />
= 2 sinucosu<br />
(From Sum Identity)<br />
(Like terms!!)<br />
cos<br />
( 2u) = cos ( u + u)<br />
= cosucosu -sinusinu<br />
2 2<br />
= cos u -sin<br />
u<br />
(From Sum Identity)<br />
tan<br />
( 2u) = tan ( u + u)<br />
tanu<br />
+ tanu<br />
=<br />
(From Sum Identity)<br />
1 - tanutanu<br />
2 tanu<br />
=<br />
2<br />
1 - tan u<br />
This is a “last resort” if you forget the Double-Angle <strong>Identities</strong>, but you will need<br />
to recall the Double-Angle <strong>Identities</strong> quickly!<br />
One possible excepti<strong>on</strong>: Since the tan 2u<br />
may prefer to remember the Sum Identity for tan u + v<br />
tan 2u<br />
( ) identity this way.<br />
( ) identity is harder to remember, you<br />
( ) and then derive the<br />
If you’re quick with algebra, you may prefer to go in reverse: memorize the<br />
Double-Angle <strong>Identities</strong>, and then guess the Sum <strong>Identities</strong>.
Memorize These Three Versi<strong>on</strong>s of the Double-Angle Identity for cos ( 2u):<br />
Let’s begin with the versi<strong>on</strong> we’ve already seen:<br />
( ) = -<br />
2 2<br />
Versi<strong>on</strong> 1: cos 2u cos u sin u<br />
Also know these two, from “left-to-right,” and from “right-to-left”:<br />
( ) = -<br />
2<br />
Versi<strong>on</strong> 2: cos 2u<br />
1 2 sin u<br />
( ) = -<br />
Versi<strong>on</strong> 3: cos 2u<br />
2 cos 2 u 1<br />
Obtaining Versi<strong>on</strong>s 2 and 3 from Versi<strong>on</strong> 1<br />
It’s tricky to remember Versi<strong>on</strong>s 2 and 3, but you can obtain them from Versi<strong>on</strong> 1<br />
by using the Pythagorean Identity sin<br />
2 u + cos<br />
2 u = 1 written in different ways.<br />
( )<br />
To obtain Versi<strong>on</strong> 2, which c<strong>on</strong>tains sin 2 u, we replace cos 2 2<br />
u with 1 - sin u .<br />
( ) = -<br />
2 2<br />
cos 2u cos u sin u<br />
= -sin<br />
u<br />
1424<br />
3<br />
( ) -<br />
from Pythagorean<br />
Identity<br />
sin<br />
2 2<br />
2 2<br />
= 1 -sin<br />
u -sin<br />
u<br />
2<br />
= 1 -2sin<br />
u<br />
( fiVersi<strong>on</strong> 2)<br />
u<br />
(Versi<strong>on</strong> 1)<br />
( )<br />
To obtain Versi<strong>on</strong> 3, which c<strong>on</strong>tains cos 2 u, we replace sin 2 2<br />
u with 1 - cos u .<br />
( ) = -<br />
2 2<br />
cos 2u cos u sin u<br />
2 2<br />
= cos u - ( -cos<br />
u)<br />
1424<br />
3<br />
from Pythagorean<br />
Identity<br />
(Versi<strong>on</strong> 1)<br />
2 2<br />
= cos u - 1 + cos u<br />
2<br />
= 2 cos u -1<br />
( fiVersi<strong>on</strong> 3)
POWER-REDUCING IDENTITIES<br />
(These are called the “Half-Angle Formulas” in Swokowski.)<br />
Memorize:<br />
Then,<br />
2 1 cos 2u<br />
sin u<br />
2<br />
1 1<br />
2<br />
or cos 2u<br />
tan u<br />
2 2<br />
= - ( ) - ( )<br />
2 1 cos 2u<br />
cos u<br />
2<br />
1<br />
2<br />
1<br />
cos 2u<br />
2<br />
= + ( ) or + ( )<br />
2<br />
u<br />
=<br />
2<br />
= - ( )<br />
sin<br />
cos u<br />
1 cos 2u<br />
1 cos 2u<br />
+ ( )<br />
Actually, you just need to memorize <strong>on</strong>e of the sin 2 u or cos 2 u identities and then<br />
switch the visible sign to get the other. Think: “sin” is “bad” or “negative”; this is<br />
a reminder that the minus sign bel<strong>on</strong>gs in the sin 2 u formula.<br />
Obtaining the Power-Reducing <strong>Identities</strong> from the Double-Angle <strong>Identities</strong> for<br />
cos 2u ( )<br />
To obtain the identity for sin 2 u, start with Versi<strong>on</strong> 2 of the cos ( 2u) identity:<br />
( ) = -<br />
2<br />
cos 2u<br />
1 2sin<br />
u<br />
2<br />
Now, solve for sin u.<br />
2<br />
2sin<br />
u = 1 - cos ( 2u)<br />
2 1 cos 2u<br />
sin u = - ( )<br />
2<br />
To obtain the identity for cos 2 u, start with Versi<strong>on</strong> 3 of the cos ( 2u) identity:<br />
( ) = -<br />
2<br />
cos 2u<br />
2 cos u 1<br />
2<br />
Now, switch sides and solve for cos u.<br />
2<br />
2cos<br />
u - 1 = cos ( 2u)<br />
2<br />
2cos<br />
u = 1 + cos ( 2u)<br />
2 1 cos 2u<br />
cos u = + ( )<br />
2