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QUESTION FOUR<br />

A student cycles to school each day. He must ride over the steep hill<br />

between his home and school. The combined mass of the bike and<br />

student is 70kg.<br />

He has a new speedometer and records his speed at various times as in<br />

the table.<br />

Time (s) 0 120 240 360 480 540 600<br />

Speed (ms -1 ) 0 2.5 2.5 1.2 1.2 9.0 0<br />

QUESTION FOUR ANSWERS<br />

For Achievement you require Part (i) OR part of (ii) correct (a)<br />

a = change in speed = 2.5 = 0.02 ms -2<br />

Change in time 120<br />

OR<br />

W=Fd - correct calculation of force or distance (units not needed) or carry<br />

through error from part (i) in F=ma<br />

This data is shown on the grid below.<br />

Speed (m s -1 )<br />

10<br />

9<br />

8<br />

7<br />

6<br />

5<br />

4<br />

3<br />

2<br />

1<br />

0<br />

0 100 200 300 400 500 600 700<br />

Time (s)<br />

(i) Calculate the acceleration of the student on his bike in the<br />

first 120 seconds.<br />

For Merit you require part (i) correct (a = 0.02 ms -2 ) AND part of (ii) with<br />

correct force or distance with unit (m)<br />

F = ma<br />

OR<br />

= 70 x 0.02 = 1.4 N (allow 1.46 if a unrounded)<br />

Distance = area under graph or d = v (av) t<br />

= 120 x 2.5<br />

2 = 150m<br />

For Excellence you require ALL answers correct with units (e)<br />

W=Fd<br />

F= ma = 70 x 0.02 = 1.4 N<br />

d = area under graph or d = v (av) t<br />

= 120 x 2.5<br />

2 = 150m<br />

(ii)<br />

Calculate the work done by the cyclist in this time.<br />

Additional Question over page<br />

W = Fd = 1.4 x 150 = 210J

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