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Internal assessment resource Chemistry 2.7A for Achievement Standard 91167<br />

PAGE FOR TEACHER USE<br />

Assessment schedule: Chemistry 91167 Redox rules<br />

Evidence/Judgements for Achievement Evidence/Judgements for Achievement with Merit Evidence/Judgements for Achievement<br />

with Excellence<br />

The student shows understanding:<br />

relevant observations are recorded<br />

For example:<br />

Bubbles/fizzing, metal dissolves<br />

Orange solution turns blue/green<br />

Purple solution turns pale yellow-brown<br />

key reactant and product species are correctly<br />

identified for three reactions<br />

For example:<br />

Mg + H + Mg 2+ + H 2<br />

Cr 2 O 2- -<br />

7 + HSO 3 Cr 3+ 2-<br />

+ SO 4<br />

MnO - 4 + Fe 2+ Mn 2+ + Fe 3+<br />

H 2 O 2 + I - I 2 + H 2 O<br />

an oxidant or reductant is identified without<br />

linking to oxidation number or electron transfer<br />

for one reaction.<br />

For example:<br />

In the first reaction H 2 O 2 is the oxidant.<br />

The student shows in-depth understanding:<br />

balanced overall equations are written for three<br />

reactions<br />

For example:<br />

Mg + 2H + Mg 2+ + H 2<br />

Cr 2 O 2- 7 +3HSO - 3 +5H + 2Cr 3+ +3SO 2- 4 +4H 2 O<br />

MnO - 4 + 8H + + 5Fe 2+ Mn 2+ + 5Fe 3+ + 4H 2 O<br />

H 2 O 2 + 2H + + 2I - I 2 + 2H 2 O<br />

observations are linked to species for three reactions<br />

For example:<br />

Metal dissolves because Mg turns to Mg 2+ .<br />

Bubbles occur because H + turns to H 2 .<br />

The solution turns from orange to green because<br />

Cr 2 O 2- 7 is orange and Cr 3+ -<br />

is blue/green. HSO 3<br />

and SO 2- 4 are colourless.<br />

MnO - 4 is purple, Fe 2+ is pale green. The resulting<br />

solution is pale yellow-brown due to the formation<br />

of Fe 3+ . Mn 2+ is colourless.<br />

Brown colour forms due to the formation of I2. All<br />

other species are colourless.<br />

oxidants and reductants are identified in terms of<br />

oxidation number or electron transfer for one reaction.<br />

For example:<br />

H 2 O 2 is the oxidant because each oxygen gains<br />

one electron or oxidation number goes from -1 to -<br />

2 in H 2 O.<br />

I - is the reductant because it loses one electron or<br />

oxidation number goes from -1 to 0.<br />

The student shows comprehensive<br />

understanding:<br />

balanced overall equations are<br />

consistently written with no errors<br />

observations are linked to species for<br />

all reactions<br />

oxidants and reductants are identified<br />

in terms of oxidation number or<br />

electron transfer for both reactions.<br />

For example:<br />

When acidified H 2 O 2 reacts, it is the<br />

oxidant because each oxygen gains<br />

one electron or oxidation number goes<br />

from -1 to -2 in H 2 O.<br />

I - is the reductant because it loses one<br />

electron or oxidation number goes<br />

from -1 to 0.<br />

When non-acidified H 2 O 2 reacts it is<br />

the reductant because each oxygen<br />

loses one electron or oxidation<br />

number goes from -1 to 0 in O 2 . I 2 is<br />

the oxidant because it gains one<br />

electron or oxidation number goes<br />

from 0 to -1.<br />

Final grades will be decided using professional judgement based on a holistic examination of the evidence provided against the criteria in the<br />

Achievement Standard.<br />

This resource is copyright © Crown 2011 Page 6 of 6

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