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Assignment Solutions CHEM 110- Fall 2011 1. Express the following ...

Assignment Solutions CHEM 110- Fall 2011 1. Express the following ...

Assignment Solutions CHEM 110- Fall 2011 1. Express the following ...

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e) 5.00 gram of glucose (C 6 H 12 O 6 ) diluted to 250 mL<br />

w<br />

% =<br />

v<br />

mass of solute (g)<br />

5.00 g<br />

x 100 %w/v glucose = x 100 = 2.00 %<br />

volume of solution (ml)<br />

250 ml<br />

Molarity =<br />

mole of solute (g)<br />

volume of solution (L)<br />

Molarity ethanol =<br />

1mole<br />

5.00 g x<br />

180 g<br />

0.250 L<br />

= 0.111 M<br />

2. A solution is prepared by dissolving 12.15 gram of Nickel (II) nitrate in 175 mL of<br />

water (density = <strong>1.</strong>00 g/ml). Calculate:<br />

a) <strong>the</strong> % w/w (mass percent)<br />

mass of solution = 12.15 g Nickel + 175 g Nickel = 187.15 g solution.<br />

w<br />

% =<br />

w<br />

mass of solute (g)<br />

mass of solution (ml)<br />

12.15 g<br />

x 100 %w/w Nickel = x 100 = 6.49 %<br />

187.15 g<br />

b) <strong>the</strong> mole fraction of Ni 2+ ions<br />

Mole Nickel ions =<br />

1mole<br />

12.15 g x = 0.207 mole Ni<br />

58.7g<br />

2+<br />

Mole of H 2 O = 175 g x<br />

1mole<br />

18 g<br />

= 9.72 mole H<br />

2<br />

O<br />

Mole fraction =<br />

2+<br />

mole of Ni<br />

2+<br />

mole of Ni + mole of<br />

H<br />

2<br />

O<br />

Mole fraction of Ni 2+ =<br />

0.207 mole<br />

0.207 mole + 9.72 mole<br />

= 0.0209

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