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NARAYANA IIT/PMT ACADEMY - Narayanaicc.com

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1<br />

0<br />

3<br />

0<br />

3<br />

<strong>NARAYANA</strong> <strong>IIT</strong>/<strong>PMT</strong> <strong>ACADEMY</strong><br />

JEE ADVANCE : 2013<br />

0<br />

E<br />

3<br />

= 3 (074) ( 2 091)<br />

E = 222 – 182<br />

E = 04V<br />

(PAPER – II) CODE: 0<br />

39 The unbalanced chemical reactions given in List I show missing reagent or condition (?) which<br />

are provided in List II Match List I with List II and select the correct answer using the code<br />

given below the lists<br />

List I<br />

List II<br />

P PbO 2 + H 2 SO 4<br />

Q Na 2 S 2 O 3 + H 2 O<br />

R N 2 H 4<br />

S XeF 2<br />

Code :<br />

P Q R S<br />

(A) 4 2 3 1<br />

(B) 3 2 1 4<br />

(C) 1 4 2 3<br />

(D) 3 4 2 1<br />

?<br />

?<br />

?<br />

?<br />

N 2 + other product<br />

PbSO 4 + O 2 + other product<br />

1 NO<br />

NaHSO 4 + other product 2 I 2<br />

3 warm<br />

Xe + other product 4 Cl 2<br />

Ans (D)<br />

warm<br />

1<br />

Sol (i) PbO 2 + H 2 SO 4 PbSO 4 + H 2 O 2 H 2 O + O<br />

2<br />

2<br />

Cl2<br />

(ii) Na 2 S 2 O 3 + H 2 O 2NaHSO 4 + NaCl<br />

(iii) N 2 H I 2<br />

4 N 2 + 2HI<br />

(iv) XeF 2 + NO Xe + NOF<br />

40 The unbalanced chemical reactions given in List I show missing reagent or condition (?) which<br />

are provided in List II Match List I with List II and select the correct answer using the code<br />

given below the lists<br />

P. Cl<br />

List I<br />

List II<br />

1 (i) Hg(OAc) 2 ; (ii) NaBH 4<br />

Q. ONa OEt<br />

2 NaOEt<br />

R.<br />

OH<br />

3 Et – Br<br />

<strong>NARAYANA</strong> GROUP OF EDUCATIONAL INSTITUTIONS - INDIA<br />

23

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