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NARAYANA IIT/PMT ACADEMY - Narayanaicc.com

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<strong>NARAYANA</strong> <strong>IIT</strong>/<strong>PMT</strong> <strong>ACADEMY</strong><br />

JEE ADVANCE : 2013<br />

S 1 represent the inside part of circle |z| = 4<br />

By putting z = x + iy, we get S2 3x y 0<br />

S 3 represent the right part of y-axis<br />

S is the shaded region in above diagram<br />

Now A<br />

2 2 2<br />

r 2 r r 20<br />

4 3 4 3 4 3<br />

54 min 1 3i z<br />

z<br />

S<br />

(PAPER – II) CODE: 0<br />

(A) 2 3 (B) 2 3 (C) 3 3 (D) 3 3<br />

2<br />

2<br />

2<br />

2<br />

Ans (C)<br />

Sol Min |1 – 3i – z| = minimum distance of point A 1, 3 z S from region S<br />

= AB distance in diagram<br />

3 3 3 3<br />

2 2<br />

Paragraph for Question 55 and 56<br />

A box B 1 contains 1 white ball, 3 red balls and 2 block balls Another box B 2 contains 2 white balls, 3 red<br />

balls and 4 black balls A third box B 3 contains 3 white balls, 4 red balls and 5 black balls<br />

55 If 1 balls is drawn from each of the boxed B 1 , B 2 the probability that all 3 drawn balls are of the<br />

same colour is<br />

(A) 82<br />

(B) 90<br />

(C) 558<br />

(D) 566<br />

648<br />

648<br />

648<br />

648<br />

Ans<br />

Sol<br />

(A)<br />

Required probability<br />

1 2 3 3 3 4 2 4 5<br />

6 9 12 6 9 12 6 9 12<br />

82<br />

648<br />

56 If 2 balls are drawn (without replacement) from a randomly selected box and one of the balls is<br />

white and the other balls is red, the probability that these 2 balls are drawn from box B 2 is<br />

(A) 116<br />

(B) 126<br />

(C) 65<br />

(D) 55<br />

181<br />

181<br />

181<br />

181<br />

Ans (D)<br />

Sol Required probability<br />

<strong>NARAYANA</strong> GROUP OF EDUCATIONAL INSTITUTIONS - INDIA<br />

33

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