SIMPLE INTEREST

More documents

Recommendations

Info

Also, from I and II, we get sum = 100 x 4500 = 15000. 10 x 3 Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained. Thus, III is redundant. Either II or III is redundant.
Page 1 and 2: SIMPLE INTEREST
Page 3 and 4: (i). Simple Intereest = P x R x T 1
Page 5 and 6: 5. Reena took a loan of Rs. 1200 wi
Page 7 and 8: 10.A sum of Rs. 725 is lent in the
Page 9 and 10: Since the principal is not given, s
Page 11 and 12: II gives, T = 10 years. Sum = 100 x
Page 13 and 14: .. Amount = ( X + 27X/50) = 77X/50
Page 15 and 16: 4% p.a. interest on principal for n
Page 17 and 18: P x T Now, I gives, S.I. = Rs. 4000
Page 19 and 20: COMPOUND INTEREST Compound interest
Page 21 and 22: Simple interest on a certain sum of
Page 23 and 24: Solution S.I C.I = Rs.(1200x10x1/10
Page 25 and 26: If the simple interest on a sum of
Page 27 and 28: 40 40 40 = Rs. 1600 x 41 41 + 1 40
Page 29 and 30: Amount = Rs. (30000 + 4347) = Rs. 3
Page 31 and 32: Amount = Rs. P 1 + R 4 100 C.I. =P
Page 33 and 34: Answer: Option D Explanation: Amoun
Page 35 and 36: 15000 (100 + R)2 - 10000 - (200 x R
Page 37 and 38: 11.The population of a town was 360
Page 39 and 40: ond as the interest that he receive
Page 41 and 42: Difference between C.I. and S.I. ma
Page 43: For this sum, C.I. and hence amount

SIMPLE INTEREST

Create successful ePaper yourself

Delete template?

Save as template?