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Budget Constraints qStart to Build a Theory of Consumer Choice ...

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Microeconomics<br />

Dr. Dmitri M. Medvedovski<br />

The <strong>Consumer</strong>’s Problem<br />

●Attain the highest possible level <strong>of</strong> utility<br />

–Scale utility mountain<br />

●The available budget constitutes the constraint<br />

●Think <strong>of</strong> the budget as a fence on the mountain<br />

●Find the highest place on the fence<br />

The <strong>Budget</strong> Constraint<br />

●The consumer has a sum <strong>of</strong> money <strong>to</strong> spend each period, M<br />

This money is spread across many goods, X i<br />

●Thus the expenditure on the first good, X 1<br />

, is<br />

●And similarly for all other goods<br />

Graphical Construction <strong>of</strong> the <strong>Budget</strong> Constraint<br />

The <strong>Budget</strong> Line in Mathematical Terms<br />

●Imagine the consumer spends all income on good Y<br />

●The maximum amount <strong>of</strong> Y that can be purchased is M/(P Y<br />

)<br />

●If all income is spent on good X then the maximum quantity is M/(P X<br />

)<br />

●Join these two points <strong>to</strong> make a straight line<br />

●Any combination on the line exhausts the entire budget M<br />

The Slope <strong>of</strong> the <strong>Budget</strong> Constraint<br />

●The slope is the ratio <strong>of</strong> the two prices: derive: (M/Py)/(M/Px)<br />

●-P Y<br />

/P X<br />

The <strong>Consumer</strong> <strong>Choice</strong><br />

●Attain highest possible utility<br />

●Don’t violate the budget constraint<br />

●<br />

<strong>Budget</strong>: I = P 1 X 1 + P 2 X 2 , where X 1 and X 2 are goods.<br />

X 2<br />

50<br />

I<br />

P 2<br />

I<br />

P 1<br />

= X 1<br />

+ P 2<br />

P 1<br />

X 2<br />

40<br />

30<br />

20<br />

Slope = -1 = − P 2<br />

P 1<br />

I<br />

X 1<br />

= I P 1<br />

− P 2<br />

P 1<br />

X 2<br />

10<br />

10 20 30 40 50<br />

X 1<br />

P 1<br />

constant<br />

slope<br />

Page 4 out <strong>of</strong> 7 Lec. 5

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