Finite Math Exam 1 Review - Faculty Web Pages
Finite Math Exam 1 Review - Faculty Web Pages
Finite Math Exam 1 Review - Faculty Web Pages
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FM Lial 9 th ed<br />
FM <strong>Exam</strong> 1 <strong>Review</strong> F09 O’Brien<br />
6b. x = # of batches of cars. y = # of batches of jets<br />
Minimize cost, C = 120x + 100y, subject to the following constraints:<br />
6x + 3y ≤ 150 2.5x + 7.5y ≤ 150 5x + 5y ≤ 150 x ≥ 0 y ≥ 0<br />
6x + 3y + s 1 = 150<br />
2.5x + 7.5y + s 2 = 150<br />
5x + 5y + s 3 = 150<br />
–120x – 100y + C = 0<br />
⎡ 6 3 1 0 0 0 150⎤<br />
⎢<br />
⎥<br />
⎢<br />
2.<br />
5 7.<br />
5 0 1 0 0 150<br />
⎥<br />
⎢ 5 5 0 0 1 0 150⎥<br />
⎢<br />
⎥<br />
⎣−120<br />
−100<br />
0 0 0 1 0 ⎦<br />
7a. Maximum f is 264 when x = 16, y = 4, z = 0, s 1 = 0, s 2 = 16, and s 3 = 0<br />
7b. Maximum f is 18 when x = 5, y = 4, z = 0, s 1 = 0, s 2 = 0, and s 3 = 15<br />
7c. x = # model A hibachis. y = # model B hibachis<br />
Maximize profit, P = 2x + 1.5y, subject to 3x + 4y ≤ 1000 6x + 3y ≤ 1200 x ≥ 0 y ≥ 0<br />
They should produce 120 model A hibachis and 160 model B hibachis to earn a maximum<br />
profit of $480. There will be no raw material left over.<br />
8a. Maximum P = 12 when x = 0, y = 6, s 1 = 0, s 2 = 15<br />
8b. Minimum C =<br />
Part Two<br />
66 3 20 12 when x = , y = , s1 = , s2 = 0, and s 3 = 0<br />
7<br />
7 7 7<br />
6