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Finite Math Exam 1 Review - Faculty Web Pages

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FM Lial 9 th ed<br />

FM <strong>Exam</strong> 1 <strong>Review</strong> F09 O’Brien<br />

6b. x = # of batches of cars. y = # of batches of jets<br />

Minimize cost, C = 120x + 100y, subject to the following constraints:<br />

6x + 3y ≤ 150 2.5x + 7.5y ≤ 150 5x + 5y ≤ 150 x ≥ 0 y ≥ 0<br />

6x + 3y + s 1 = 150<br />

2.5x + 7.5y + s 2 = 150<br />

5x + 5y + s 3 = 150<br />

–120x – 100y + C = 0<br />

⎡ 6 3 1 0 0 0 150⎤<br />

⎢<br />

⎥<br />

⎢<br />

2.<br />

5 7.<br />

5 0 1 0 0 150<br />

⎥<br />

⎢ 5 5 0 0 1 0 150⎥<br />

⎢<br />

⎥<br />

⎣−120<br />

−100<br />

0 0 0 1 0 ⎦<br />

7a. Maximum f is 264 when x = 16, y = 4, z = 0, s 1 = 0, s 2 = 16, and s 3 = 0<br />

7b. Maximum f is 18 when x = 5, y = 4, z = 0, s 1 = 0, s 2 = 0, and s 3 = 15<br />

7c. x = # model A hibachis. y = # model B hibachis<br />

Maximize profit, P = 2x + 1.5y, subject to 3x + 4y ≤ 1000 6x + 3y ≤ 1200 x ≥ 0 y ≥ 0<br />

They should produce 120 model A hibachis and 160 model B hibachis to earn a maximum<br />

profit of $480. There will be no raw material left over.<br />

8a. Maximum P = 12 when x = 0, y = 6, s 1 = 0, s 2 = 15<br />

8b. Minimum C =<br />

Part Two<br />

66 3 20 12 when x = , y = , s1 = , s2 = 0, and s 3 = 0<br />

7<br />

7 7 7<br />

6

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