Chapter 4 Numerical Differentiation And Integration
Chapter 4 Numerical Differentiation And Integration
Chapter 4 Numerical Differentiation And Integration
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
I = 4I n − I n/2<br />
− 12d 4<br />
+ ...<br />
3 n 4<br />
Define Ĩ = (4I n − I n/2 )/3 then the error convergence order increasing from O(1/n 2 ) to<br />
O(1/n 4 ).<br />
• Romberg integration<br />
The Richardson’s extrapolation process can be continued inductively. Define<br />
I (k)<br />
n<br />
with n a multiple of 2 k , k ≥ 1.<br />
= 4k I n<br />
(k−1)<br />
I (0)<br />
1<br />
4 k − 1<br />
I (0)<br />
2 I (1)<br />
2<br />
− I (k−1)<br />
n/2<br />
I (0)<br />
4 I (1)<br />
4 I (2)<br />
4<br />
I (0)<br />
8 I (1)<br />
8 I (2)<br />
8 I (3)<br />
8<br />
... ... ... ...<br />
4.7 <strong>Numerical</strong> <strong>Differentiation</strong><br />
From the Newton’s interpolation polynomial,<br />
, n ≥ 2 k<br />
f(x) − p n (x) = Φ n (x)f[x 0 ,x 1 ,...,x n ,x], Φ n (x) = (x − x 0 )...(x − x n )<br />
f ′ (x) − p ′ n(x) = Φ ′ n(x)f[x 0 ,x 1 ,...,x n ,x] + Φ n (x)f[x 0 ,x 1 ,...,x n ,x,x]<br />
= Φ ′ n(x) f(n+1) (ξ 1 )<br />
(n + 1)!<br />
Thus let x j = x 0 + jh, j = 0, 1,...,n. Then<br />
+ Φ n (x) f(n+2) (ξ 2 )<br />
(n + 2)!<br />
Φ n (x) = O(h n+1 ), Φ ′ n(x) = O(h n )<br />
f ′ (x) − p ′ n(x) =<br />
{<br />
O(h n ) Φ ′ n(x) ≠ 0<br />
O(h n+1 ) Φ ′ n(x) = 0<br />
10