10.07.2015 Views

ASPECTS OF IWASAWA THEORY OVER FUNCTION FIELDS 1 ...

ASPECTS OF IWASAWA THEORY OVER FUNCTION FIELDS 1 ...

ASPECTS OF IWASAWA THEORY OVER FUNCTION FIELDS 1 ...

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

<strong>IWASAWA</strong> <strong>THEORY</strong> <strong>OVER</strong> <strong>FUNCTION</strong> <strong>FIELDS</strong> 15respect to norm maps). For two finite extensions L ⊃ L ′ ⊃ F , the degree maps deg L anddeg L ′ fit into the commutative diagram (with exact rows)(5.1) A(L) M(L)deg L Z pN L L ′A(L ′ ) N L L ′ M(L ′ )deg L ′ Z p ,where N L L ′ denotes the norm and the vertical map on the right is multiplication by [F L : F L ′](the degree of the extension between the fields of constants). For an infinite extension L/Fcontained in F, taking projective limits (and recalling Assumption 5.1 above), one gets anexact sequence(5.2) A(L) M(L)deg L Z p .Remark 5.2. If one allows non-geometric extensions then the deg L map above becomes thezero map exactly when the Z p -extension F arit is contained in L.It is well known that M(F d ) is a finitely generated torsion Λ(F d )-module (see e.g. [19,Theorem 1]), so the same holds for A(F d ) as well. Moreover take any Z d p-extension F d of Fcontained in F: since our extension F/F is totally ramified at the prime p, for any F d−1 ⊂ F done has(5.3) M(F d )/I F dF d−1M(F d ) ≃ M(F d−1 )(see for example [48, Lemma 13.15]). As in Section 3, to ease notations we will often erasethe F from the indices (for example I F dF d−1will be denoted by Id−1 d ), hoping that no confusionwill arise. Consider the following diagram(5.4) A(F d ) M(F d ) deg Z pγ−1γ−1A(F d ) γ−1 M(F d ) deg Z p(where 〈γ〉 = Gal(F d /F d−1 ) =: Γ d d−1; note also that the vertical map on the right is 0) andits snake lemma sequence(5.5) A(F d ) Γd d−1 M(F d ) Γd d−1deg Z pdegZ p M(F d )/Id−1 d M(F d) A(F d )/Id−1 d A(F d) .For d ≥ 2 the Λ d -module Z p is pseudo-null, hence (5.2) yields Ch Λd (M(F d )) = Ch Λd (A(F d )),and, using (5.3) and (5.5), one finds (for d ≥ 3)(5.6)Ch Λd−1 (A(F d )/I d d−1 A(F d)) = Ch Λd−1 (M(F d )/I d d−1 M(F d))= Ch Λd−1 (M(F d−1 )) = Ch Λd−1 (A(F d−1 ))(where all the modules involved are Λ d−1 -torsion modules).Let(5.7) N(F d ) ↩→ A(F d )ι−→ E(F d ) ↠ R(F d )

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!