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1. How many grams of Cl2 can be prepared from the reaction of ...

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6. Which <strong>of</strong> <strong>the</strong> following contains <strong>the</strong> greatest num<strong>be</strong>r <strong>of</strong> atoms?A. 100 g <strong>of</strong> Pb MW = 207, so this is ~ ½ mol.B. 2.0 mole <strong>of</strong> Ar this is 2 mol.C. 0.1 mole <strong>of</strong> Fe this is 0.1 mol.D. 5 g <strong>of</strong> He MW = 4, so this is ~ 1¼ mol.E. 20 million O 2 molecules this is a tiny fraction <strong>of</strong> a mole7. <strong>How</strong> <strong>many</strong> atoms are <strong>the</strong>re in <strong>1.</strong>00 ng <strong>of</strong> magnesium? (1 g = 1 x 10 9 ng)A. 4.11 x 10 -11 atomsB. 2.48 x 10 13 atomsC. 6.83 x 10 -35 atomsD. 6.02 x 10 14 atomsE. <strong>1.</strong>46 x 10 34 atoms9<strong>1.</strong>0 x10g 1mol.Mg 6.02 x10atoms<strong>1.</strong>00 ng x x x= 2.48 x101ng 24.3 g Mg 1mol.2313atoms8. What is <strong>the</strong> coefficient <strong>of</strong> H 2 O when <strong>the</strong> following equation is properly balanced with smallest set <strong>of</strong> whole num<strong>be</strong>rs?_1_ Al 4 C 3 + _12_ H 2 O → _4_ Al(OH) 3 + _3_ CH 4A. 3B. 4C. 6D. 12E. 249. <strong>How</strong> <strong>many</strong> moles <strong>of</strong> oxygen atoms are contained in 10 moles <strong>of</strong> KClO 3 (potassium chlorate)?A. 3 molB. 3.3 molC. 10 molD. 30 molE. 6.02 x 10 24 mol10 mol. KClO3 mol. Ox1mol. KClO3 =330 mol. O10. Identify <strong>the</strong> major ionic species present in an aqueous solution <strong>of</strong> Na 2 CO 3 .A. Na 2 + CO 32-B. Na 2 + , C 2- O 3C. Na + , C 4+ , O 32-D. Na + , C + , O 2-E. Na + , CO 32-1<strong>1.</strong> The distinguishing characteristic <strong>of</strong> all electrolyte solutions is that <strong>the</strong>yA. contain molecules.B. conduct electricity. (that is why it is called electrolyte)C. react with o<strong>the</strong>r solutions.D. always contain acids.E. conduct heat.


12. In accordance with <strong>the</strong> solubility rules, which <strong>of</strong> <strong>the</strong> following is true when solutions containing about 0.1 g <strong>of</strong>Pb(NO 3 ) 2 (aq) and 100 mL <strong>of</strong> 0.200 M KI(aq) are mixed?Pb(NO 3 ) 2 (aq) + 2KI(aq) → PbI 2 (s) + 2KNO 3 (aq)A. KNO 3 will precipitate; Pb 2+ and I - are spectator ions.B. No precipitate will form.C. Pb(NO 3 ) 2 will precipitate; K + and I - are spectator ions.D. PbI 2 will precipitate; K + and NO - 3 are spectator ions.E. Pb 2+ and I - are spectator ions, and PbI 2 will precipitate.13. In accordance with <strong>the</strong> solubility rules, which <strong>of</strong> <strong>the</strong> following is true when solutions <strong>of</strong> CuSO 4 (aq) and BaCl 2 (aq) aremixed?CuSO 4 (aq) + BaCl 2 (aq) → CuCl 2 (aq) + BaSO 4 (s)A. CuCl 2 will precipitate, and Ba 2+ and SO 2- 4 are spectator ions.B. CuSO 4 will precipitate, and Ba 2+ and Cl - are spectator ions.C. BaSO 4 will precipitate, and Cu 2+ and Cl - are spectator ions.D. BaCl 2 will precipitate, and Cu 2+ and SO 2- 4 are spectator ions.E. No precipitate will form.14. The common constituent in all acid solutions isA. H 2B. H + This is <strong>the</strong> Bronsted definition <strong>of</strong> an acidC. OH -D. H 2 SO 4E. Cl -15. Which is <strong>the</strong> chemical formula <strong>of</strong> <strong>the</strong> salt produced by neutralization <strong>of</strong> nitric acid with calcium hydroxide?2HNO 3 + Ca(OH) 2 → Ca(NO 3 ) 2 + H 2 OA. CaNO 3B. Ca 2 (NO 2 ) 3C. Ca(NO 2 ) 2D. Ca 2 NO 3E. Ca(NO 3 ) 216. The oxidation num<strong>be</strong>r <strong>of</strong> S in K 2 SO 4 isA. +6B. +4C. +2D. -1E. none <strong>of</strong> <strong>the</strong>m(2 x K) + S + (4 x O) = 0(2 x +1) + S + (4 x -2) = 0S = 617. The oxidation num<strong>be</strong>r <strong>of</strong> Fe in K 3 Fe(CN) 6 isA. +3B. +2C. +1D. -3E. -4(3 x K) + Fe + (6 x CN - ) = 0 (it is important to recall that CN has a -1 charge)(3 x +1) + Fe + (6 x -1) = 0Fe = 3


18. Which one <strong>of</strong> <strong>the</strong> following is a redox <strong>reaction</strong>?A. H + (aq) + OH - (aq) → H 2 O(l)B. 2KBr(aq) + Pb(NO 3 ) 2 (aq) → 2KNO 3 (aq) + PbBr 2 (s)C. CaBr 2 (aq) + H 2 SO 4 (aq) → CaSO 4 (s) + 2HBr(g)D. 2Al(s) + 3H 2 SO 4 (aq) → Al 2 (SO 4 ) 3 (aq) + 3H 2 (g) Al 0 → Al 3+ and H + → H 0E. CO 2- 3 + HSO - 4 → HCO - 2-3 + SO 419. In <strong>the</strong> following <strong>reaction</strong> <strong>the</strong> oxidizing agent is5S + 6KNO 3 + 2CaCO 3 → 3K 2 SO 4 + 2CaSO 4 + CO 2 + 3N 2A. S S 0 → S 6+ S is oxidized, thus it is <strong>the</strong> reducing agentB. N 2 N 2 is a productC. KNO 3 N 5+ → N 0 N is reduced, thus <strong>the</strong> KNO 3 must <strong>be</strong> <strong>the</strong> oxidizing agentD. CaSO 4E. CaCO 320. What element is oxidized in <strong>the</strong> following <strong>reaction</strong>?Cd + NiO 2 + 2H 2 O → Cd(OH) 2 + Ni(OH) 2A. Cd Cd 0 → Cd 2+B. NiC. OD. H2<strong>1.</strong> When 0.860 g <strong>of</strong> an organic compound containing C, H, and O was burned completely in oxygen, <strong>1.</strong>64 g <strong>of</strong> CO 2 and<strong>1.</strong>01 g <strong>of</strong> H 2 O were produced. What is <strong>the</strong> empirical formula <strong>of</strong> <strong>the</strong> compound?1mol.CO 2 1mol. C0.0373 mol.A. CHOC : <strong>1.</strong>64 g CO 2 xx = 0.0373 mol. C= 2 mol.C44.0 g CO 2 1mol.CO 20.0189 mol.B. CH 2 OC. C 2 H 4 O1mol. H 2O2 mol. H0.111mol.H : <strong>1.</strong>01g H 2 O x x= 0.111mol. H= 6 mol. HD. C 2 H 6 O18.0 g H 2O1mol. H 2O0.0189 mol.E. C 3 H 6 O 2 ⎛1mol.C ⎞ ⎛1mol.H ⎞O : 0.860 g sample -⎜0.0373 mol.C x - 0.111mol.H = 0.302 g O12.0 g C⎟⎜x<strong>1.</strong>01g H⎟⎝⎠ ⎝⎠1mol.O0.0189 mol.O : 0.302 g O x = 0.0189 mol.O= 1mol. O16.0 g O0.0189 mol.Thus C 2 H 6 O22. What is <strong>the</strong> mass percent <strong>of</strong> Cu in 10 g CuSO 4 ?A. 0.398%B. <strong>1.</strong>51%C. 2.51%D. 39.8%E. 66.1%g Cu63.5 gx100%=x100%= 39.8 %g Cu + g S + g O 63.5 g + 32.1g + 4(16.0) g

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