Differential Equations on the two dimensional torus 1 Constant ...
Differential Equations on the two dimensional torus 1 Constant ...
Differential Equations on the two dimensional torus 1 Constant ...
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November 1, 2010 9b-5Let us write this system (3) in polar coordinates.We havex = rcos(θ), y = rsin(θ)ẋ = ṙcos(θ) − rsin(θ) ˙θẏ = ṙsin(θ) + rcos(θ) ˙θ(4)So, we see that <strong>the</strong> simple polar coordinate systemṙ = 0˙θ = ω(5)is equivalent to (4).The soluti<strong>on</strong>s off (0, 0) arer = c > 0, θ(t) = ω t + θ 0 .Hence, <strong>the</strong> orbits in <strong>the</strong> plane off (0, 0) c<strong>on</strong>sist of <strong>the</strong> circles r = c and<strong>the</strong> moti<strong>on</strong> has c<strong>on</strong>stant rotati<strong>on</strong>al speed ω with period 2π ω .Now, c<strong>on</strong>sider <strong>two</strong> uncoupled springs whose equati<strong>on</strong>s in R 4 becomex˙1 = −ω 1 y 1y˙1 = ω x 1(6)x˙2 = −ω 2 y 2y˙2 = ω 2 x 2Using polar coordinates (r 1 , θ 1 , r 2 , θ 2 ) in R 4 in <strong>the</strong> obvious way, we get<strong>the</strong> equivalent equati<strong>on</strong>sr˙1 = 0θ˙1 = ω 1(7)r˙2 = 0θ˙2 = ω 2Hence all soluti<strong>on</strong>s in R 4 off <strong>the</strong> uni<strong>on</strong> of <strong>the</strong> <strong>two</strong> subspaces R 2 ×{(0, 0} ⋃ {0, 0}×R 2 lie <strong>on</strong> <strong>two</strong> dimensi<strong>on</strong>al tori r 1 = c 1 , r 2 = c 2 , and <strong>the</strong> moti<strong>on</strong> <strong>on</strong> each is ac<strong>on</strong>stant vector field. If ω 2 /ω 1 is rati<strong>on</strong>al, <strong>the</strong>n all <strong>the</strong>se orbits are periodic,and if ω 2 /ω 1 is irrati<strong>on</strong>al, <strong>the</strong>n all <strong>the</strong>se tori are minimal sets.