Numerical solution of the 2+1 Teukolsky equation on a ...

Conclusion - Formulas for s ≠ 0 with ID0 and ID2· at R + :{µ l =l 0 + l + 3 + b −1 for l ′ = l 0 , l 0 + 1l ′ + l + 2 + b −1 for l ′ > l 0 + 1· at ˜R:{µ l =l 0 + l + 3 −1 for l ′ = l 0 , l 0 + 1l ′ + l + 2 −1 for l ′ > l 0 + 1· at J + :⎧⎨ l − s + 2 −1 for l ′ = l 0 , l 0 + 1µ l = l ′ − s + 1 −1⎩l − s + 2 −1for l ′ > l 0 + 1 and l < l ′for l ′ > l 0 + 1 and l ≥ l ′, where l 0 = max(|s|, |m|) is <strong>the</strong> lowest excitable modeand b = 0 in general but b = 1 for <strong>the</strong> special case s > 0, m = 017 / 20