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ベイズの 公 式 の 導 出{ A,B} Pr{ A B} Pr{ B}Pr ={ A,B} Pr{ B A} Pr{ A}Pr =ABPrPr14 January, 2010{ A B}=={ B } Pr{ A,B}= ∑APrPrPr{ A,B}{ B}{ B A} Pr{ A}∑APr=Pr{ A,B}{ B A} Pr{ A}=Pr{ B}∑APr{ B A} Pr{ A}{ B A} Pr{ A}PrHokkaido University GCOE Tutorial(Sapporo) 19
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