12.07.2015 Views

Vol. 10 No 3 - Pi Mu Epsilon

Vol. 10 No 3 - Pi Mu Epsilon

Vol. 10 No 3 - Pi Mu Epsilon

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PROBLEMS AND SOLUTIONS 24 1then xy' - alx = axy + bgY, ory' = c + ay + bxy,subject to the conditions y(0) = 0 and y' (0) = c. To solve this system wemake the substitution y = u exp(ax + b212) and we getu = c exp(-ax - b&) with u(0) = 0 and u'(0) = c.xFrom this equation we obtain the solution u = c f exp(-at - bt 2 /2) dt and0r 1 r 1842. [Fall 19941 Proposed by Russell Euler, <strong>No</strong>rthwest Missouri StateUniversity, Mary ville, Missouri.Let xi be a positive real number for i = 1, 2, . . . , n. Prove that- -with equality if and only if xl = x2 = ... = x,,.Solution by Joe Howard, New Mexico Highlands University, Las Vegas,New Mexico.By the Cauchy-Schwartz inequality we have thatWe observe that the integral exists for all x and hence that the given seriesconverges. Since S = y(l), we obtains = c exp [(a 1: [- $1 exp (a dtor equivalently,andCombining (1) and (2) we get thatIf b > 0, then by making the substitution a + bt = uJb, we canobtainwhere $(-r) is the cumulative function of the normal probability distribution,defined bya .Also solved by <strong>Mu</strong>rray S. Klamkin, and the Proposer.and the theorem follows. It is easy to see that we have equality if and onlyifxl = x2 = ... = xn.Also solved by Miguel Amengual Covas, Seung-Jin Bang, Scott H.Brown, Paul S. Bruckman, Philip A. D. Castoro, William Chau, RichardI. Hess, <strong>Mu</strong>rray S. Klamkin, Henry S. Lieberman, David E. Manes, Can.A. Minh, Yoshinobu <strong>Mu</strong>rayoshi, Bob Prielipp, St. Olaf Problem SolvingGroup, Selvaratnam Sridharma, Sammy Yu and Jimmy Yu, and theProposer.Klarnkin showed more generally that

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