6 <strong>250</strong> PROBLEMS IN NUMBER THEORY65* . . F<strong>in</strong>d an <strong>in</strong>creas<strong>in</strong>g arithmetic progression with the least differenceformed of <strong>in</strong>tegers and conta<strong>in</strong><strong>in</strong>g no term of the Fibonacci sequence.66*. F<strong>in</strong>d a progression ak +b (k = 0, 1, 2, ... ), with positive <strong>in</strong>tegers aand b such that (a, b) = 1, which does not conta<strong>in</strong> any term of Fibonaccisequence.67. Prove that the arithmetic progression ak+b (k = 0, 1, 2, ... ) withpositive <strong>in</strong>tegers a and b such that (a, b) = 1 conta<strong>in</strong>s <strong>in</strong>f<strong>in</strong>itely many termspairwise relatively prime.68*. Prove that <strong>in</strong> each arithmetic progression ak+b (k = 0, 1, 2, ... )with positive <strong>in</strong>tegers a and b there exist <strong>in</strong>f<strong>in</strong>itely many terms with the sameprime divisors.69. From the theorem of Lejeune-Dirichlet, assert<strong>in</strong>g that each arithmeticprogression ak+b (k = 0, 1, 2, ... ) with relatively prime positive <strong>in</strong>tegers aand b conta<strong>in</strong>s <strong>in</strong>f<strong>in</strong>itely many primes, deduce that for every such progressionand every positive <strong>in</strong>teger s there exist <strong>in</strong>f<strong>in</strong>itely many terms which areproducts of s dist<strong>in</strong>ct primes.70. F<strong>in</strong>d all arithmetic progressions with difference 10 formed of morethan two primes.71. F<strong>in</strong>d all arithmetic progressions with difference 100 formed of morethan two primes.72*. F<strong>in</strong>d an <strong>in</strong>creas<strong>in</strong>g arithmetic progression with ten terms, formedof primes, with the least possible last term.73. Give an example of an <strong>in</strong>f<strong>in</strong>ite <strong>in</strong>creas<strong>in</strong>g arithmetic progressionformed of positive <strong>in</strong>tegers such that no term of this progression can berepresented as a sum or a difference of two primes.IV. PRIME AND COMPOSITE NUMBERS74. Prove that for every even n > 6 there exist primes p and q suchthat (n-p, n-q) = 1.75. F<strong>in</strong>d all primes which can be represented both as sums and asdifferences of two primes.76. F<strong>in</strong>d three least positive <strong>in</strong>tegers n such that there are no primesbetween nand n + 10, and three least positive <strong>in</strong>tegers m such that thereare no primes between 10m and lO(m+l).
PROBLEMS 777. Prove that every prime of the form 4k + 1 is a hypotenuse of a rectangulartriangle with <strong>in</strong>teger sides.78. F<strong>in</strong>d four solutions of the equation p2+ 1 = q2+r2 with primes p,q, and r.79. Prove that the equation p2+q2 = r2+s2+t2 has no solution withprimesp, q, r, s, t.80*. F<strong>in</strong>d all prime solutions p, q, r of the equation p(p+l)+q(q+l)= r(r+l).81*. F<strong>in</strong>d all primesp, q, and r such that the numbers p(p+l), q(q+l),r(r+ 1) form an <strong>in</strong>creas<strong>in</strong>g arithmetic progression.82. F<strong>in</strong>d all positive <strong>in</strong>tegers n such that each of the numbers n+ 1,n+3, n+7, n+9, n+13, and n+15 is a prime.83. F<strong>in</strong>d five primes which are sums of two fourth powers of <strong>in</strong>tegers.84. Prove that there exist <strong>in</strong>f<strong>in</strong>itely many pairs of consecutive primeswhich are not tw<strong>in</strong> primes.85. Us<strong>in</strong>g the theorem of Lejeune-Dirichlet on arithmetic progressions,prove that there exist <strong>in</strong>f<strong>in</strong>itely many primes which do not belong to anypair of tw<strong>in</strong> primes.86. F<strong>in</strong>d five least positive <strong>in</strong>tegers for which n 2 -1 is a product ofthree different primes.87. F<strong>in</strong>d five least positive <strong>in</strong>tegers n for which n 2 + 1 is a product ofthree different primes, and f<strong>in</strong>d a positive <strong>in</strong>teger n for which n 2 + 1 is aproduct of three different odd p~mes.88*. Prove that among each three consecutive <strong>in</strong>tegers > 7 at leastone has at least two different prime divisors.89. F<strong>in</strong>d five least positive <strong>in</strong>tegers n such that each of the numbers n,n+ 1, n+2 is a product of two different primes. Prove that there are nofour consecutive positive <strong>in</strong>tegers with this property. Show by an examplethat there exist four positive <strong>in</strong>tegers such that each of them has exactlytwo different prime divisors.90. Prove that the theorem assert<strong>in</strong>g that there exist only f<strong>in</strong>itely manypositive <strong>in</strong>tegers n such that both nand n+ 1 have only one prime divisoris equivalent to the theorem assert<strong>in</strong>g that there exist only f<strong>in</strong>itely manyprime Mersenne numbers and f<strong>in</strong>itely many prime Fermat numbers.
- Page 5: 250 PROBLEMSIN ELEMENTARY NUMBER TH
- Page 17: PROBLEMS 553. Prove that for every
- Page 21 and 22: PROBLIMS 9contains at least one pri
- Page 23 and 24: PROBLEMS 11128*. From a particular
- Page 25 and 26: •• oaLEHS13153. Prove that the
- Page 27 and 28: PROBLEMS 15167*. Prove that for eve
- Page 29 and 30: PROBLEMS 17189. Using the identity(
- Page 31 and 32: PROBLEMS 19209*. Prove that the sum
- Page 33 and 34: PRO.LlMS 21positive integers which
- Page 35 and 36: SOLUTIONSI. DIVISIBILITY OF NUMBERS
- Page 37 and 38: SOLUTIONS 2510. These are all odd n
- Page 39 and 40: SOLUTIONS 2716. We have 312 3 +1, a
- Page 41 and 42: SOLUTIONS 29Since HI = 2"+2 > H, th
- Page 43 and 44: SOLUTIONS 31Since 2 3 - 3 (mod 5) a
- Page 45 and 46: SOLUTIONS 3333. The condition (x, y
- Page 47 and 48: SOLUTIONS3S'2, '3, while n > 3, the
- Page 49 and 50: SOLUTIONS 37a, b, c give three diff
- Page 51 and 52: SOLUTIONS 39hence a+b+c ~ 5+7+9 ~ 2
- Page 53 and 54: SOLUTIONS 41rectangular triangle wi
- Page 55 and 56: SOLUTIONS 43= 1. If we had plQ, the
- Page 57 and 58: SOLUTIONS 4566*. The progression ll
- Page 59 and 60: SOLUTIONS 47primes, then the differ
- Page 61 and 62: SOLUTIONS 49have, for example, 52 =
- Page 63 and 64: SOLUTIONS 51The least such number i
- Page 65 and 66: SOLUTIONS 53n 2 -1 is a product of
- Page 67 and 68: SOLUTIONSssnumbers are consecutive
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SOLUTIONS 57The problem arises whet
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SOLunONSS9which implies that 2 N /p
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SOLUTIONS 61follows that we must ha
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SOLUTIONS 63to note that (for k = 1
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SOLUTIONS 65(where p > F4)' Let us
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SOLUTIONS 67171 (34k+2)22 +1, 171 (
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SOLUTIONS 69Obviously, gk(X) is a p
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SOLUTIONS 7130t+r where t is an int
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SOLUTIONS 73136. We easily find tha
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SOLUTIONS 75145. Our equation is eq
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SOLUTIONS 77If we had 161d, then by
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SOLUTIONS 79154*. LEMMA. If a, b, c
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SOLUTIONS 81157. Suppose that theor
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SOLUTIONS 83160. We must have x ::;
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SOLUTIONS 85f h Ill h' h' I' 2 1 6I
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SOLUTIONS 87For s = 3, the equation
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SOLUTIONS89We must therefore have X
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SOLUTIONS 91integer s at least one
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SOLUTIONS 93k is an integer> 3, the
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SOLUTIONS95REMARK.One can prove tha
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SOLUTIONS 97= 2 x , hence Y > 1, an
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SOLUTIONS 99then 2Zk(zz+l) = y3_1 =
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SOLUTIONS 101MISCELLANEA200. The eq
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SOLUTIONS 103The assertion can be s
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SOLUTIONS 1052" == [(mod 2k), and c
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SOLUTIONS 107for instance [a] + I,
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SOLUTIONS 109225*. We shall prove b
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SOLUTIONS 111itive integers, as in
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SOLUTIONS113We may assume that u ~
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SOLUTIONS 115square. On the other h
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SOLUTIONS 117namely numbers 13 and
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SOLUTIONS 119For positive integers
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SOLUTIONS 12124S. Computing the val
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124 REFERENCES24. W. Sierpmski, Sur
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The late Waclaw SierpiJiski, a memb