Algebra/Trig Review - Pauls Online Math Notes - Lamar University

Algebra/Trig ReviewThe solution in this case is [ −3, − 1) . We don’t include the -1 because this is wherethe solution is zero, but we do include the -3 because this makes the expression zero.Absolute Value Equations and InequalitiesSolve each of the following.1. 3x + 8 = 2SolutionThis uses the following factp = d ≥0⇒ p=±dThe requirement that d be greater than or equal to zero is simply an acknowledgementthat absolute value only returns number that are greater than or equal to zero. SeeProblem 3 below to see what happens when d is negative.So the solution to this equation is3x+ 8= 2 3x+ 8=−23x=− 6 OR 3x=−10x = −2 10x = −3So there were two solutions to this. That will almost always be the case. Also, do notget excited about the fact that these solutions are negative. This is not a problem. Wecan plug negative numbers into an absolute value equation (which is what we’redoing with these answers), we just can’t get negative numbers out of an absolutevalue (which we don’t, we get 2 out of the absolute value in this case).2. 2x − 4 = 10© 2006 Paul Dawkins 42http://tutorial.math.lamar.edu/terms.aspx