Band-pass and equivalent low-pass signal modeling
Band-pass and equivalent low-pass signal modeling
Band-pass and equivalent low-pass signal modeling
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Recovery of quadrature component xFourier transforming we get− jωct 11j2ωct{ } = 2 { } + 2 { }1 j2ωct ∗ − j2ωct4 [ ]vt ( )Re e Re ~ z() t Re ~ z()te1= xt () + ~ zte () + ~ zt () e2(12)121~ ~X( f)+ 4 Z ( f − 2f ) + Z ( − f − 2f)∗[ ]cc(13)The transform components are b<strong>and</strong>limited Õ<strong>low</strong><strong>pass</strong>filtering the result we get 1/2 X(f) or[ {− ω}]c2xt () = vt ()Ree j t LP(14)© NOKIA FILENAME.PPT / 13.12.1997 / NN page: 13
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