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Ex 2.2 answer.pdf

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<strong>2.2</strong> Sine13SolutionBC= sin 32°ABBC = AB sin 32°= 52 × sin 32°= 27.6SolutionACQ = sin 52°AB∴ AC = AB · sin 52°= 33 × sin 52°= 26.0<strong>Ex</strong>tra <strong>Ex</strong>ample 5Find AB and BC in the figure below.(Give the <strong>answer</strong>s correct to 2 decimal places.)SolutionB25 20’C3AHave a TryFind AB and AC in the figure below.(Give the <strong>answer</strong>s correct to 2 decimal places.)C1246 24’ABSolutionAC= sin 25°20′ABACAB =sin 25° 20'3=sin 25° 20′= 7.01In ∆ABC,AB 2 = AC 2 + BC 2BC 2 = AB 2 – AC 2= 7.011 2 – 3 2= 40.154BC = 6.34(Pyth. Theorem)BCQ= sin 46°24′ABBC∴ AB =sin 46° 24′12=sin 46° 24′In ∆ABC,= 16.57AB 2 = AC 2 + BC 2AC 2 = AB 2 – BC 2= 16.571 2 – 12 2= 130.587∴ AC = 11.43(Pyth. Theorem)

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