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Name: ANSWER KEY - Bama.Ua.Edu - The University of Alabama

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<strong>Name</strong>: <strong>ANSWER</strong> <strong>KEY</strong> (print) CWID:<br />

Chemistry 231, Fall 2011<br />

Dr. Shaughnessy<br />

Exam #2-Version 1<br />

October 11 th , 2011<br />

Honor Pledge: I promise or affirm that I will not at any time be involved with cheating,<br />

plagiarism, fabrication, or misrepresentation while enrolled as a student at <strong>The</strong> <strong>University</strong> <strong>of</strong><br />

<strong>Alabama</strong>. I have read the Academic Honor Code, which explains disciplinary procedures that<br />

will result from the aforementioned. I understand that violation <strong>of</strong> this code will result in<br />

penalties as severe as indefinite suspension from the <strong>University</strong>.<br />

_____________________________(signature)<br />

You will have 1 hour and 20 minutes to complete this exam. When<br />

time is called please stop all work and turn in your exam.<br />

Show all work. Partial credit will be given where appropriate.<br />

This exam has 9 pages. Make sure you have all 9 pages, and that they<br />

are correctly copied, before starting the exam. <strong>The</strong> last page has useful<br />

information for you.<br />

You may use molecular models to help you answer questions on this<br />

exam.<br />

You will not need a calculator or any other electronic device to complete<br />

this exam.<br />

Please put all cell phones (turn <strong>of</strong>f or to silent), ipods, calculators, or<br />

other electronic devices away in a book bag.<br />

Your book and all notes should be placed out <strong>of</strong> sight <strong>of</strong> yourself and<br />

your neighbors before the exam begins.


Version 1: White<br />

Problem Score<br />

1 (12)<br />

2 (20)<br />

3 (22)<br />

4 (18)<br />

5 (16)<br />

6 (16)<br />

Total (100)<br />

<strong>The</strong>re are a total <strong>of</strong> 104 points, but the exam<br />

is worth 100 points.<br />

2


Version 1: White<br />

1. For each problem below, circle the best answer. In each case, there is only one correct<br />

answer (12 points)<br />

a. Which substituent would have the highest priority in the Cahn-Ingold-Prelog rules? <strong>The</strong><br />

point <strong>of</strong> attachment to the stereocenter is the arrow.<br />

F<br />

I<br />

b. Which molecule below is not chiral?<br />

O<br />

B O<br />

F<br />

CH 3<br />

c. Which carbocation would be the most stable?<br />

d. Which molecule below would not have an index <strong>of</strong> hydrogen deficiency <strong>of</strong> 3?<br />

O<br />

Br<br />

e. Which molecule below is a meso compound?<br />

Br<br />

Br<br />

H 3C<br />

C<br />

f. Which molecule below would be least likely to act as a Lewis acid in a reaction?<br />

H Cl<br />

F F O<br />

Br OH<br />

H<br />

B<br />

H H<br />

N<br />

Mg 2+<br />

OH<br />

Br F CH HO OH<br />

3<br />

CH3 HO 2C<br />

CH 3<br />

Br<br />

H 3C CH 3<br />

Br<br />

SnH 3<br />

CO 2H<br />

3


Version 1: White<br />

2. For each reaction below, provide the missing starting material(s) or product(s). Provide the<br />

starting material that would give the provided product as the only product. Draw the major<br />

product or products expected. You may ignore stereochemistry in drawing the starting<br />

materials or products. (20 points)<br />

a.<br />

b.<br />

c.<br />

d.<br />

O<br />

N<br />

O<br />

OH<br />

+<br />

+<br />

HBr<br />

S<br />

+ HCl<br />

H 2O<br />

H 2SO 4 (cat)<br />

Two products formed<br />

O<br />

N<br />

O<br />

O<br />

Br<br />

OH<br />

Cl<br />

Cl<br />

H<br />

S<br />

4


Version 1: White<br />

3. Stereocenter configurations and nomenclature. (22 points)<br />

a. Provide the missing name for compound below. Be sure to indicate any stereochemical<br />

configurations in your name.<br />

(4Z,6S)-2,6-dimethyl-3,5-dipropyl-2,4-octadiene<br />

b. For each molecule below, provide the R/S or E/Z configurations for each chiral center or<br />

stereogenic alkene.<br />

O<br />

O<br />

F<br />

F<br />

Circle the highest priority<br />

substituents on each alkene<br />

carbon and assign as E or Z<br />

Z<br />

Dextromethorphan-cough suppressent in<br />

Robutussin, Nyquil, Vicks, Dimetapp, etc<br />

H 3CO<br />

N<br />

H<br />

CH 3<br />

3<br />

2<br />

2<br />

H<br />

1<br />

4<br />

3<br />

S<br />

Label the substituents on each circled<br />

chiral center in order <strong>of</strong> priority and then<br />

assign the R or S configuration<br />

b. Label each pair <strong>of</strong> molecule below as identical, enantiomers, or diastereomers.<br />

H 2N H<br />

H NH2<br />

Cl<br />

Cl<br />

Diastereomers<br />

S<br />

4<br />

1<br />

HO<br />

H<br />

Br<br />

HO H<br />

Br<br />

Enantiomers<br />

5


Version 1: White<br />

4. Compare the acidity <strong>of</strong> the two amines shown below. (18 points)<br />

a. Draw the key resonance structures that help to stabilize the negative charge in the<br />

conjugate bases below.<br />

i.<br />

ii.<br />

H<br />

O<br />

H<br />

O<br />

NH 2<br />

NH 2<br />

C<br />

O<br />

NH<br />

H<br />

-H +<br />

-H +<br />

H<br />

H<br />

O<br />

NH<br />

b. Which compound would you predict to be more acidic? In 2 sentences, or less, support<br />

your answer.<br />

NH<br />

<strong>The</strong> molecule in part i is more acidic. It has one additional resonance structure than ii,<br />

where the negative charge can be moved onto the oxygen.<br />

NH<br />

C<br />

O<br />

<strong>The</strong>re is no way to move the negative<br />

charge onto the aldehyde oxygen<br />

O<br />

NH<br />

H<br />

C<br />

O<br />

H<br />

H<br />

H<br />

O<br />

O<br />

NH<br />

NH<br />

NH<br />

NH<br />

C<br />

O<br />

C<br />

O<br />

H<br />

H<br />

6


Version 1: White<br />

5. For each reaction below, circle the side <strong>of</strong> the reaction that would be favored. You have not<br />

been provided pKa values, so use your knowledge <strong>of</strong> how the structure <strong>of</strong> an acid affects its<br />

relative acidity. Provide a short (one sentence) explanation for the direction <strong>of</strong> the<br />

equilibrium. (16 points)<br />

a.<br />

b.<br />

c.<br />

d.<br />

H 3CS<br />

O<br />

OH<br />

A<br />

O<br />

O<br />

+ +<br />

Cl<br />

H<br />

O<br />

3CS<br />

O<br />

B is a stronger acid than A because Cl is a stronger inductive electron-withdrawing<br />

group than SCH 3.<br />

F + HCl HF + Cl<br />

HCl is a stronger acid than HF because Cl is larger than F (lower on periodic table).<br />

O<br />

O<br />

NH<br />

O<br />

+ H N +<br />

O<br />

N is more electronegative than C, so the N-H bond is more acidic.<br />

H C N + C C H<br />

C N + H C C H<br />

HCN is a stronger acid than acetylene because <strong>of</strong> the higher inductive<br />

withdrawing effect <strong>of</strong> N vs. C.<br />

O<br />

O<br />

O<br />

O<br />

H<br />

H<br />

Cl<br />

O<br />

B<br />

7<br />

OH


Version 1: White<br />

6. Shown below is the synthesis <strong>of</strong> methyl tert-butyl ether (MTBE). MTBE was used as a<br />

gasoline additive, but its use was discontinued due to problems with it contaminating<br />

groundwater. Provide a detailed mechanism for this reaction that shows each intermediate.<br />

Use arrows to show electron motion and indicate any formal charges. Note that the reactivity<br />

<strong>of</strong> methanol (CH3OH) is similar to that <strong>of</strong> water. (16 points)<br />

+<br />

+ HOCH 3<br />

H<br />

O CH3 H<br />

(from HOCH 3<br />

and H 2SO 4)<br />

H<br />

O CH3<br />

H<br />

H 2SO 4<br />

(cat)<br />

+ HOCH 3<br />

OCH 3<br />

methyl tert-butyl ether (MTBE)<br />

H<br />

HOCH 3<br />

OCH 3<br />

H<br />

+ O CH 3<br />

H<br />

H<br />

8


Version 1: White<br />

9

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