28.08.2015 Views

Mathematical Pedagogy

Mathematical Pedagogy - IRMACS Centre

Mathematical Pedagogy - IRMACS Centre

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Mean Menger Curvature<br />

Given a circle through three points (Menger circle), is there a<br />

point on the spanned interval with the same curvature?<br />

Suppose f and g are both twice differentiable on [a, b],<br />

that k(f) < k(g) on [a, b], and that f(a) = g(a).<br />

If f (a)<br />

g (a) then<br />

for all x in (a, b],<br />

f(x) g(x):<br />

QuickTime and a<br />

TIFF (Uncompressed) decompressor<br />

are needed to see this picture.<br />

QuickTime and a<br />

TIFF (Uncompressed) decompressor<br />

are needed to see this picture.<br />

QuickTime and a<br />

TIFF (Uncompressed) decompressor<br />

are needed to see this picture.<br />

QuickTime and a<br />

TIFF (Uncompressed) decompressor<br />

are needed to see this picture.<br />

QuickTime and a<br />

TIFF (Uncompressed) decompressor<br />

are needed to see this picture.<br />

QuickTime and a<br />

TIFF (Uncompressed) decompressor<br />

are needed to see this picture.<br />

If g has constant curvature (is part of a circle) and<br />

k(f) ≠ k(g) on [a, b] then f and g can intersect<br />

at most twice.<br />

19<br />

If f (a)<br />

g (a) th en<br />

for at most one x in<br />

(a, b],<br />

f (x) = g(x).<br />

Therefore there must<br />

be a point s on [a, b]<br />

at which<br />

k(f(s)) = Menger Curvature<br />

of the points a, b, c.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!