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Model Subwoofer Loudspeaker Thiele / Small Parameters Recommended ...

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eclipse_sub<br />

3/8/10 5:07 PM<br />

88-Ti<br />

88100Ti-<br />

DVC<br />

26 0.47 2.10 84 3.1+3.1 750/1500 5.6 0.51 1.5" 345.0 0.65<br />

Sealed<br />

1.0<br />

Sealed<br />

1.50<br />

Sealed<br />

2.0<br />

10<br />

Sealed 7/8"<br />

9 1/4" 7 ½" 0.18<br />

CuFt<br />

88120Ti-<br />

DVC<br />

27 0.30 3.20 89 3.1+3.1 750/1500 5.0 0.32 1.5" 490.0 0.75<br />

Sealed<br />

1.20<br />

Sealed<br />

1.75<br />

Sealed<br />

2.5<br />

12 ¾" 11 3/16" 8 ½" 0.19<br />

Sealed CuFt<br />

88150Ti-<br />

DVC<br />

27 0.39 6.10 91 3.1+3.1 750/1500 5.0 0.42 1.75" 800.0 0.85<br />

Sealed<br />

1.25<br />

Sealed<br />

2.0 Sealed 3.0<br />

Sealed<br />

15<br />

9/16"<br />

13.15/16" 9 ¾" 0.30<br />

CuFt<br />

All Enclosure Volumes are calculated in CuFt (Cubic Feet).<br />

The dimensions are calculated against a constant... 1728<br />

Example: Boxes Standard<br />

Using Fig-1. Multiply the HxWxD (in Inches) and then divide this number against a constant of 1728. Assume values for Fig-1 as:<br />

H=12" W=18" D=12". Calculated values become: 12" x 18" x 12" = 2592". Take the value of 2595 and divide it against constant<br />

1728. 2592"/1728 = 1.5 CuFt.<br />

Why 1728? Well this is because 1-CuFt (Cubic Ft) is really 1-Ft x<br />

1-Ft x 1-Ft (Height (H) x Width (D) x Depth (D). Therefore if 0ne<br />

foot = 12" then it stands to reason that 12" x 12" x 12" also equals<br />

1-cubic Ft.<br />

Note: 12" x 12" x 12"=1728" (1-Cubic Ft)<br />

Example 2. Wedges: Simplified Approach<br />

Now lets try calculating an angled enclosure like that shown in Fig-2. The simplest way to do<br />

this is to create two (2) rectangular boxes. Square off the top of the box at the angle point. (See<br />

Fig-3)<br />

In Fig-3, We calculate the rectangle formed in Box-A portion (Just like we did in the<br />

Fig-1 Box example) Record this value. Next add enough size to the box in Fig-3, to be<br />

able to make a new complete rectangle as shown in Box-B.<br />

Next calculate Box-B volume (same way as Fig-1 Box).<br />

Divide this Box-B volume by 2, so that we obtain 1/2 of its original value. Add this Box-<br />

B 1/2 volume to the Box-A volume, for the ENCLOSURES TOTAL VOLUME.<br />

file:///Users/lisacook/Desktop/eclipse_sub.webarchive<br />

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