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Differential Calculus I (A-Class)

Differential Calculus I (A-Class) - Talent 100

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HSC STYLE HOMEWORK<br />

NAME: .................................................<br />

SEMINAR DAY & TIME: ........................<br />

w w w . t a l e n t - 1 0 0 . c o m . a u 1 3 0 0 9 9 9 1 0 0<br />

Preliminary Mathematics Extension 1<br />

<strong>Differential</strong> <strong>Calculus</strong> I (A-<strong>Class</strong>)<br />

General Instructions<br />

• Reading time – 5 minutes<br />

• Working time – 2 hours<br />

• Write using black or blue pen<br />

• Draw diagrams in pencil<br />

• Board-approved calculators may<br />

be used<br />

• A table of standard integrals may<br />

be used<br />

• All necessary working should be<br />

shown in every question<br />

Total marks – 60<br />

• Attempt Questions 1-7<br />

• All questions are of equal value


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

Total marks – 60<br />

Attempt Questions 1–5<br />

All questions are of equal value<br />

Question 1 (12 marks)<br />

Marks<br />

The Second Derivative<br />

is the second derivative of , i.e. we differentiate twice<br />

(a)<br />

For each of the following functions, find <br />

.<br />

(i) = + 3 + 2 + 1 2<br />

(ii) = + 2 4 − 3 3<br />

(iii)<br />

= <br />

<br />

3<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 2 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

Concavity<br />

(b) Concavity is a measure of the curvature of the slope, i.e whether it is curving upwards or curving<br />

downwards.<br />

When a curve is concave down, < 0<br />

When a curve is concave up, > 0<br />

(b) Determine the concavity of the following curves at the point where = 5.<br />

(i) = + 2 − 5 + 3 − 1 2<br />

(ii) = 3 − 5 2<br />

End of Question 1<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 3 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

Marks<br />

Question 2 (12 marks)<br />

Stationary Points<br />

The second derivative will be positive for a min, i.e. > 0 for a max<br />

The second derivative will be negative for a max, i.e. < 0 for a max<br />

If = 0, the result is inconclusive and points will need to be tested<br />

Points of Inflexion<br />

STEP 1: Find the values of for which = 0<br />

STEP 2: Use a table of values to determine to determine the sign of around its zeroes. The<br />

second derivative must change sign for a point of inflexion.<br />

(a) For a particular function, it is known that = − √ − 2.<br />

(i) Suppose a stationary point exists at = 6. Determine the nature of 2<br />

the stationary point.<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 4 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

(ii) Find the values of for which has a point of inflexion. 2<br />

(iii) Find the values of for which is concave down. 2<br />

A Horizontal Point of Inflexion is a point around which the sign of does not change, but the<br />

sign of does change<br />

The tangent crosses the curve<br />

At a Horizontal Point of Inflexion, = 0 and = 0<br />

NOTE: = = 0 is not enough to prove a horizontal point of inflexion. Always<br />

remember to test points<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 5 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

(b) Consider the function = − − 8 + 32 + 1.<br />

(i) Find the coordinates of any stationary points and determine their nature. 3<br />

(ii) Find the coordinates of any points of inflexion. 2<br />

(iii) Briefly sketch the graph of = . 1<br />

End of Question 2<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 6 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

Question 3 (12 marks)<br />

Marks<br />

(a) Consider the function = <br />

√ .<br />

(i) State the domain of . 1<br />

(ii) Show that is concave down for all in its domain. 3<br />

(iii) Hence, find the coordinates of any stationary points of and 2<br />

determine their nature.<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 7 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

(iv) Neatly sketch the graph of = , showing all important features. 2<br />

(b) (i) Show that 0 = 0 = 0 given that = . 2<br />

(ii) Hence or otherwise, determine the nature of the stationary point at = 0. 2<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

End of Question 3<br />

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Page 8 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

Question 4 (12 marks)<br />

Marks<br />

(a)<br />

The diagram below shows the graph of = .<br />

−2,3<br />

<br />

0,1<br />

−4,0<br />

<br />

(i) On separate axis, sketch the graphs of = and = . 3<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 9 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

(ii) On separate axis, sketch possible graphs of = and = given 4<br />

that = , and that has a stationary point at 0,0.<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 10 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

(b)<br />

A particular function = + + + , has a horizontal point of inflexion<br />

at the point (1,3), where , and are constants.<br />

(i) Find expression for and . 2<br />

(ii) Find the values of , and . 3<br />

End of Question 4<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 11 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

Question 5 (12 marks)<br />

Marks<br />

(a) A particular function is defined by = <br />

.<br />

(i) State the domain of . 1<br />

(ii) Find the coordinates of any turning points, and determine their nature. 4<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 12 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

(iii) Find the coordinates of any points of inflexion 2<br />

(iv) Explain why − ≤ ≤ . 2<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

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Page 13 of 14


PMX Homework <strong>Differential</strong> <strong>Calculus</strong> I © TALENT 100<br />

(v) Hence, neatly sketch the graph of = , clearly showing all turning 3<br />

points, points of inflexion and intercepts with the coordinate axis.<br />

End of paper<br />

TALENT 100: HSC SUCCESS. SIMPLIFIED.<br />

www.talent-100.com.au<br />

Page 14 of 14

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