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Practice test is like a Xerox copy of actual GB0-180 exam because no. of questions, pattern, format and timing is same as actual GB0-180 exam. Due to simulation of GB0-180 exam, you can easily judge the circumstances and other important facts about the GB0-180 exam and can reduce your chances of failure. With the help of GB0-180 exam Practice test you will get 100% guaranteed success.
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<strong>Exam</strong> Code: <strong>GB0</strong><strong>180</strong><br />
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Huawei<br />
<strong>GB0</strong>-<strong>180</strong><br />
<strong>Exam</strong> Name:<br />
Huawei Certified Network Eng<strong>in</strong>eer<br />
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Question: 1.<br />
Which of the follow<strong>in</strong>g is the function of the session layer( )<br />
A. To provide encryption/decryption<br />
B. To provide data conversion and format<br />
C. To set up connections between different hosts<br />
D. To set up session between two applications<br />
Answer: D<br />
Question: 2.<br />
Which of the follow<strong>in</strong>g command is usually used for remote logg<strong>in</strong>( )<br />
A. PING<br />
B. TRACERT<br />
C. TELNET<br />
D. IPCONFIG<br />
Answer: C<br />
Question: 3.<br />
( ) is a k<strong>in</strong>d of broadcast, through which the host can dynamically discover the MAC address<br />
correspond<strong>in</strong>g to one IP address<br />
A. ARP<br />
B. DNS<br />
C. ICMP<br />
D. RARP<br />
Answer: A<br />
Question: 4.<br />
I<br />
EEE802.3 Ethernet adopts ( ) to support bus topology ,it is abbreviated from ( ).<br />
A. STP Spann<strong>in</strong>g Tree Protocol<br />
B. STP Shortest Tree Protocol<br />
C. CSMA/CD Carrier Sense Multicast Access/Collision Detection<br />
D. CSMA/CD Carrier Sent Multicast Access/CRC Detection<br />
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E. CSMA/CD Carrier Service Multiple Access/Collision Detection<br />
F. CSMA/CD Carrier Sense Multiple Access/Collision Detection<br />
Answer: B<br />
Question: 5.<br />
The basic functions of transport layer are:<br />
A. Segment upper-layer data<br />
B. Create end-to-end connection<br />
C. Transmit data from the host at one end to the host at the other end<br />
D. Ensure the stability of data transmission<br />
Answer: ABCD<br />
Question: 6.<br />
The pr<strong>in</strong>ciple used to evaluate the rout<strong>in</strong>g algorithm does NOT <strong>in</strong>clude( )<br />
A. Fast convergence<br />
B. Flexibility<br />
C. Advancement <strong>in</strong> topology structure<br />
D. If the path selected is the best<br />
Answer: C<br />
Question: 7.<br />
In the router, which of the follow<strong>in</strong>g command can be used to view the rout<strong>in</strong>g table of a router( )<br />
A. ARP -A<br />
B. TRACERT<br />
C. ROUTE PRINT<br />
D. DISPLAY IP ROUTING-TABLE<br />
Answer: D<br />
Question: 8.<br />
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Input display <strong>in</strong>terface on Huawei Quidway router, and which of the follow<strong>in</strong>g <strong>in</strong>formation you will<br />
see?<br />
A. The descriptions about the <strong>in</strong>terface<br />
B. The route <strong>in</strong>formation concern<strong>in</strong>g the said <strong>in</strong>terface<br />
C. Error statistics<br />
D. Interface status<br />
Answer: ACD<br />
Question: 9.<br />
Which of the follow<strong>in</strong>g authentication algorithms are used for ppp authentication?<br />
A. MD5<br />
B. PAP<br />
C. CHAP<br />
D. IPsec<br />
Answer: BC<br />
Question: 10.<br />
RouterA and RouterB are connected by serial <strong>in</strong>terface.The configuration of router A is as below:<br />
[Quidway1]display current-configurtion<br />
Now create configuration...<br />
Current configuration<br />
!<br />
version 1.74<br />
local-user huawei service-type ppp password simple quidway firewall enable<br />
sysname Quidway1<br />
!<br />
<strong>in</strong>terface Aux0<br />
async mode flow<br />
phy-mru 0<br />
l<strong>in</strong>k-protocol ppp<br />
!<br />
<strong>in</strong>terface Ethernet0<br />
ip address 1.1.1.1 255.0.0.0<br />
!<br />
<strong>in</strong>terface Serial0<br />
clock DTECLK1<br />
l<strong>in</strong>k-protocol ppp<br />
ppp authentication-mode chap<br />
ppp chap user hw<br />
ip address 2.1.1.1 255.0.0.0<br />
!<br />
<strong>in</strong>terface Serial1<br />
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l<strong>in</strong>k-protocol ppp<br />
!<br />
quit<br />
ip route-static 0.0.0.0 0.0.0.0 2.1.1.2 preference 60<br />
!<br />
return<br />
The configuration of router B is as below:<br />
[Quidway2]display current-configurtion<br />
Now create configuration...<br />
Current configuration<br />
!<br />
version 1.74<br />
local-user hw service-type ppp password simple quidway<br />
firewall enable<br />
sysname Quidway2<br />
encrypt-card fast-switch<br />
!<br />
<strong>in</strong>terface Aux0<br />
async mode flow<br />
phy-mru 0<br />
l<strong>in</strong>k-protocol ppp<br />
!<br />
<strong>in</strong>terface Ethernet0<br />
ip address 3.1.1.1 255.0.0.0<br />
!<br />
<strong>in</strong>terface Serial0<br />
l<strong>in</strong>k-protocol ppp<br />
ppp chap user huawei<br />
ppp chap password simple quidway<br />
ip address 2.1.1.2 255.0.0.0<br />
!<br />
<strong>in</strong>terface Serial1<br />
l<strong>in</strong>k-protocol ppp<br />
!<br />
quit<br />
ip route-static 0.0.0.0 0.0.0.0 2.1.1.1 preference 60<br />
!<br />
return<br />
WAN stands for serial l<strong>in</strong>k between RouterA serial <strong>in</strong>terface and RouterB serial <strong>in</strong>terface. LAN stands<br />
for the l<strong>in</strong>k between RouterA Ethernet <strong>in</strong>terface and RouterB Ethernet <strong>in</strong>terface. Which of the<br />
follow<strong>in</strong>g statements is true( )<br />
A. Both WAN and LAN can be connected<br />
B. Neither WAN, nor LAN can be connected<br />
C. The WAN on two ends can be connected, while LAN can not<br />
D. The WAN on two ends can not be connected, while LAN can be connected<br />
Answer: C<br />
Question: 11.<br />
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Frame-relay is a ( ) protocol<br />
A. connection-oriented<br />
B. network<br />
C. connectionless<br />
D. reliable<br />
Answer: A<br />
Question: 12.<br />
What is the mean<strong>in</strong>g of the number "7" <strong>in</strong> the command "fr map ip 10.1.1.1 dlci 7 broadcast"?<br />
A. The number of local logic channel<br />
B. The number of local DLCI<br />
C. The number of <strong>in</strong>terface at the opposite end<br />
D. The number of node at the opposite end<br />
Answer: B<br />
Question: 13.<br />
In RIP protocol, which of the follow<strong>in</strong>g parameter is used to computes metric( )<br />
A. MTU<br />
B. Delay<br />
C. Bandwidth<br />
D. Route hop count<br />
Answer: D<br />
Question: 14.<br />
The dynamic rout<strong>in</strong>g protocol has advantages over the static rout<strong>in</strong>g <strong>in</strong>:<br />
A. Less bandwidth occupation<br />
B. Simplicity<br />
C. The router can discern the network changes automatically<br />
D. The router can compute new routes automatically<br />
Answer: CD<br />
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Question: 15<br />
Which of the follow<strong>in</strong>g commands to configure default route is correct:<br />
A. [Quidway]ip route-static 0.0.0.0 0.0.0.0 172.16.2.1<br />
B. [Quidway]ip route-static 0.0.0.0 255.255.255.255 172.16.2.1<br />
C. [Quidway-serial0]ip router-static 0.0.0.0 0.0.0.0 172.16.2.1<br />
D. [Quidway]ip router-static 0.0.0.0 0.0.0.0 172.16.2.1<br />
Answer: A<br />
Question: 16.<br />
E0 and E1 of a Quidway router are connected to two network sections. E0 (its IP address is 10.1.1.1<br />
and its subnet mask is<br />
255.255.255.0) is connected to network A, and E1 (its IP address is 10.1.2.1 and its subnet mask is<br />
255.255.255.0) is connected to<br />
network B<br />
Question: which<br />
of the follow<strong>in</strong>g hosts can p<strong>in</strong>g host successfully <strong>in</strong> network A?<br />
A. A host <strong>in</strong> network A whose IP address is 10.1.1.12 and subnet mask is 255.255.0.0<br />
B. A host <strong>in</strong> network A whose IP address is 10.1.2.16 and subnet mask is 255.255.0.0<br />
C. A host <strong>in</strong> network B whose IP address is 10.1.2.14 and subnet mask is 255.255.255.0<br />
D. A host <strong>in</strong> network A whose IP address is 10.1.1.8 and subnet mask is 255.255.255.0<br />
Answer: ACD<br />
Question: 17.<br />
The range of the numeric ID of the standard access control list is( )<br />
A. 1~50<br />
B. 1~99<br />
C. 1~100<br />
D. 1~199<br />
E. Specified by the network management staff<br />
Answer: B<br />
Question: 18<br />
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. The access control list [Quidway] acl 100 [Quidway-acl-100] rule permit ip source 129.38.1.1<br />
0.0.255.255 dest<strong>in</strong>ation 202.38.5.2 0.0.0.0, means:<br />
A. Permit host 129.38.1.1 to access host 202.38.5.2<br />
B. Permit 129.38.0.0 network to access network 202.38.0.0<br />
C. Permit host 202.38.5.2 to access network 129.38.0.0<br />
D. Permit 129.38.0.0 network to access host 202.38.5.2<br />
Answer: D<br />
Question: 19.<br />
To check the application of access control list at a specified <strong>in</strong>terface, which of the follow<strong>in</strong>g<br />
commands is required?<br />
A. display acl<br />
B. display acl all<br />
C. display acl acl-number<br />
D. dispaly acl <strong>in</strong>terface <strong>in</strong>terface-type <strong>in</strong>terface-number<br />
Answer: D<br />
Question: 20.<br />
The fixed length part of IP packet header is ( ) bytes<br />
A. 10<br />
B. 20<br />
C. 30<br />
D. 60<br />
Answer: B<br />
Question: 21.<br />
Which transmission layer protocol does TFTP server use, and what is the port number?<br />
A. UDP 69<br />
B. TCP 67<br />
C. TCP 23<br />
D. UDP 53<br />
Answer: A<br />
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Question: 22<br />
. Under TCP protocol, to create a connection requires ( ) process; the term<strong>in</strong>ation of a connection<br />
requires ( ) process<br />
A. Direct handshake; 2 handshakes<br />
B. 2 handshakes; 4 handshakes<br />
C. 3 handshakes; 4 handshakes<br />
D. 4 handshakes; 2 handshakes<br />
Answer: C<br />
Question: 23.<br />
The command to enable Circular DDR is ( )<br />
A. dialer-rule<br />
B. acl<br />
C. dialer-group<br />
D. dialer enable-circular<br />
Answer: D<br />
Question: 24<br />
In ISDN network, U <strong>in</strong>terface is def<strong>in</strong>ed between ( )<br />
A. TE1 and NT<br />
B. TE2 and TA<br />
C. NT1 and ISDN network<br />
D. NT1 and NT2<br />
Answer: C<br />
Question: 25.<br />
To configure one virtual circuit on X.25 to be logic channel, the correct configuration is( )<br />
A. x25 map 1.1.1.2 x121-address 2202 logic-channel 1<br />
B. x25 map ip 1.1.1.2 x121-address 2202 logic-channel 1<br />
C. x25 map protocol ip 1.1.1.2 x121-address 2202 logic-channel 1<br />
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D. x25 map ip 1.1.1.2 2202 logic-channel 1<br />
Answer: B<br />
Question: 26.<br />
The command 'standby timer enable-delay ;standby timer disable-delay' is applied when:<br />
A. Active <strong>in</strong>terface is physical <strong>in</strong>terface<br />
B. Standby <strong>in</strong>terface is physical <strong>in</strong>terface<br />
C. Active <strong>in</strong>terface is logic channel<br />
D. Standby <strong>in</strong>terface is logic channel<br />
Answer: AC<br />
Question: 27.<br />
For one network with the subnet address 5.32.0.0, and the mask 255.224.0.0, the maximum host<br />
address is( )<br />
A. 5.32.254.254<br />
B. 5.32.255.254<br />
C. 5.63.255.254<br />
D. 5.63.255.255<br />
Answer: C<br />
Question: 28.<br />
VLSM means:<br />
A. Variable Length Subnet Mask<strong>in</strong>g<br />
B. Variable Length Shortest Mask<strong>in</strong>g<br />
C. Very Long/Shortest Mask<strong>in</strong>g<br />
D. Variable Long Subnet Mask<strong>in</strong>g<br />
E. Variable Length Short Measurement<br />
Answer: A<br />
Question: 29.<br />
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For network card to connect the Ethernet <strong>in</strong>terface of a router, ( ) should be used between the two<br />
<strong>in</strong>terfaces<br />
A. Cross cable<br />
B. Standard cable<br />
C. Console cable<br />
D. AUX cable<br />
Answer: A<br />
Question: 30.<br />
Quidway R1603/1604 router provides ISDN BRI <strong>in</strong>terfaces, where Quidway R1603 provides<br />
A. S/T <strong>in</strong>terface<br />
B. U <strong>in</strong>terface<br />
C. E1 <strong>in</strong>terface<br />
D. T <strong>in</strong>terface<br />
Answer: A<br />
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