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Engineering Economy 2012

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4 Chapter 1 Foundations of <strong>Engineering</strong> <strong>Economy</strong><br />

Year 2006 2007 2008 2009 2010<br />

Average Cost, $/repair 525 430 619 650 625<br />

What range of repair costs should the engineer use to ensure that the analysis is sensitive to<br />

changing warranty costs?<br />

Solution<br />

At first glance the range should be approximately –25% to 15% of the $570 average cost to<br />

include the low of $430 and high of $650. However, the last 3 years of costs are higher and<br />

more consistent with an average of $631. The observed values are approximately 3% of this<br />

more recent average.<br />

If the analysis is to use the most recent data and trends, a range of, say, 5% of $630 is recommended.<br />

If, however, the analysis is to be more inclusive of historical data and trends, a range<br />

of, say, 20% or 25% of $570 is recommended.<br />

The criterion used to select an alternative in engineering economy for a specific set of estimates<br />

is called a measure of worth . The measures developed and used in this text are<br />

Present worth (PW) Future worth (FW) Annual worth (AW)<br />

Rate of return (ROR) Benefit/cost (B/C) Capitalized cost (CC)<br />

Payback period Economic value added (EVA) Cost Effectiveness<br />

All these measures of worth account for the fact that money makes money over time. This is the<br />

concept of the time value of money.<br />

Time value of money<br />

It is a well-known fact that money makes money. The time value of money explains the change<br />

in the amount of money over time for funds that are owned (invested) or owed (borrowed).<br />

This is the most important concept in engineering economy.<br />

The time value of money is very obvious in the world of economics. If we decide to invest<br />

capital (money) in a project today, we inherently expect to have more money in the future than<br />

we invested. If we borrow money today, in one form or another, we expect to return the original<br />

amount plus some additional amount of money.<br />

<strong>Engineering</strong> economics is equally well suited for the future and for the analysis of past cash<br />

flows in order to determine if a specific criterion (measure of worth) was attained. For example,<br />

assume you invested $4975 exactly 3 years ago in 53 shares of IBM stock as traded on the New<br />

York Stock Exchange (NYSE) at $93.86 per share. You expect to make 8% per year appreciation,<br />

not considering any dividends that IBM may declare. A quick check of the share value shows it<br />

is currently worth $127.25 per share for a total of $6744.25. This increase in value represents a<br />

rate of return of 10.67% per year. (These type of calculations are explained later.) This past<br />

i nvestment has well exceeded the 8% per year criterion over the last 3 years.<br />

1.2 Performing an <strong>Engineering</strong> <strong>Economy</strong> Study<br />

An engineering economy study involves many elements: problem identification, definition of the<br />

objective, cash flow estimation, financial analysis, and decision making. Implementing a structured<br />

procedure is the best approach to select the best solution to the problem.<br />

The steps in an engineering economy study are as follows:<br />

1. Identify and understand the problem; identify the objective of the project.<br />

2. Collect relevant, available data and define viable solution alternatives.<br />

3. Make realistic cash flow estimates.<br />

4. Identify an economic measure of worth criterion for decision making.

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