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Taylor Series Expansion

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with h = 0.2<br />

y 1 = y 0 + h f(x 0 , y 0 ) = 1.0 + 0.2*0.0/1.0 = 1.0<br />

y 2 = y 1 + h f(x 1 , y 1 ) = 1.0 + 0.2*0.2/1.0 = 1.0400<br />

y 3 = y 2 + h f(x 2 , y 2 ) = 1.0400 + 0.2*0.4/1.0400 = 1.1169<br />

y 4 = y 3 + h f(x 3 , y 3 ) = 1.1169 + 0.2*0.6/1.1169 = 1.2243<br />

y 5 = y 4 + h f(x 4 , y 4 ) = 1.2243 + 0.2*0.8/1.2243 = 1.3550

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