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Basic Electronics for Scientists and Engineers

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180 Oscillators<br />

The second of our voltage loop equations gives<br />

I b = V cc − V be1<br />

R B2<br />

. (7.13)<br />

So far our analysis is general. If the transistor is saturated, however, then I c =<br />

Ic<br />

sat ≈ V cc /R L1 (cf. Fig. 7.10). Also, to drive the transistor into saturation, the base<br />

current should be more, <strong>for</strong> a given I c , than it would be in the linear active region.<br />

Thus, I b > Ic<br />

sat/β<br />

1,whereβ 1 is the current gain factor <strong>for</strong> transistor 1. Using<br />

Eq. (7.13) <strong>for</strong> I b <strong>and</strong> the above approximation <strong>for</strong> Ic<br />

sat , we obtain<br />

or, rearranging,<br />

V cc − V be1<br />

R B2<br />

> V cc<br />

β 1 R L1<br />

(7.14)<br />

( )<br />

Vcc − V be1<br />

β 1 > R B2<br />

. (7.15)<br />

V cc R L1<br />

A similar analysis <strong>for</strong> the circuit driving transistor 2 yields<br />

( )<br />

Vcc − V be2<br />

β 2 > R B1<br />

. (7.16)<br />

V cc R L2<br />

Equations (7.11), (7.15), <strong>and</strong>(7.16), then, place important operating restrictions<br />

on our circuit component values in addition to those (Eqs. (7.8) <strong>and</strong> (7.9)) thatset<br />

the timing.<br />

7.2.3 The 555 timer<br />

The 555 timer is another “black box” device that can be used <strong>for</strong> a number of<br />

purposes. It comes in an 8-pin package similar to the 741 op-amp. A functional<br />

schematic of this device including pin assignments is shown in Fig. 7.11. Thisis<br />

sufficient <strong>for</strong> us to underst<strong>and</strong> how the device functions. We have three resistors that<br />

<strong>for</strong>m a flexible voltage divider, two comparators (basically, op-amps), a transistor,<br />

<strong>and</strong> a new device called a flip-flop. The flip-flop has two outputs, labeled Q <strong>and</strong> ¯Q,<br />

which have opposite states: when Q is high, ¯Q is low, <strong>and</strong> vice versa. The output<br />

Q is available at pin 3, while ¯Q is fed to the base of the transistor, thus turning<br />

the transistor on or off. The flip-flop also has two inputs, called set <strong>and</strong> reset. A<br />

high input into set causes Q to go high (i.e., to be set), while a low input into reset<br />

causes Q to go low (i.e., to be reset). The voltage into set comes from the output of<br />

comparator 1 which compares the voltage on pin 2 with an internal voltage derived

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