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Physics (Part 1 - Part 3)

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3.2 | Components of a Vector 61<br />

So x-components are added only to x-components, and y-components only to<br />

y-components. The magnitude and direction of R S can subsequently be found with<br />

Equations 3.3 and 3.4.<br />

Subtracting two vectors works the same way because it’s a matter of adding the<br />

negative of one vector to another vector. You should make a rough sketch when<br />

adding or subtracting vectors, in order to get an approximate geometric solution<br />

as a check.<br />

■ EXAMPLE 3.3<br />

Take a Hike<br />

GOAL Add vectors algebraically and find the<br />

resultant vector.<br />

PROBLEM A hiker begins a trip by first walking<br />

25.0 km 45.0° south of east from her base camp.<br />

On the second day she walks 40.0 km in a direction<br />

60.0° north of east, at which point she discovers<br />

a forest ranger’s tower. (a) Determine the<br />

components of the hiker’s displacements in the<br />

first and second days. (b) Determine the components<br />

of the hiker’s total displacement for the<br />

trip. (c) Find the magnitude and direction of the<br />

displacement from base camp.<br />

STRATEGY This problem is just an application<br />

of vector addition using components, Equations<br />

3.5. We denote the displacement vectors on the<br />

first and second days by A S<br />

and B S , respectively.<br />

Using the camp as the origin of the coordinates, we get the vectors shown in Figure 3.12a. After finding x- and y-components<br />

for each vector, we add them “componentwise.” Finally, we determine the magnitude and direction of the resultant<br />

vector R S , using the Pythagorean theorem and the inverse tangent function.<br />

SOLUTION<br />

(a) Find the components of A S .<br />

Camp 0<br />

y (km)<br />

20<br />

10<br />

10<br />

20<br />

a<br />

S<br />

A<br />

W<br />

R S<br />

N<br />

S<br />

E<br />

45.0 20 30 40<br />

60.0<br />

B S<br />

Tower<br />

x (km)<br />

y (km)<br />

20<br />

10<br />

R y = 16.9 km<br />

0<br />

u<br />

x (km)<br />

O 10 20 30 40<br />

R<br />

10 x = 37.7 km<br />

20<br />

Figure 3.12 (Example 3.3) (a) Hiker’s path and the resultant vector. (b) Components<br />

of the hiker’s total displacement from camp.<br />

b<br />

R S<br />

Use Equations 3.2 to find the components of A S :<br />

Find the components of B S :<br />

(b) Find the components of the resultant vector,<br />

R S 5 A S 1 B S .<br />

To find R x<br />

, add the x-components of A S and B S :<br />

To find R y<br />

, add the y-components of A S and B S :<br />

(c) Find the magnitude and direction of R S .<br />

Use the Pythagorean theorem to get the magnitude:<br />

Calculate the direction of R S using the inverse tangent<br />

function:<br />

A x<br />

5 A cos (245.0°) 5 (25.0 km)(0.707) 5 17.7 km<br />

A y<br />

5 A sin (245.0°) 5 2(25.0 km)(0.707) 5 217.7 km<br />

B x<br />

5 B cos 60.0° 5 (40.0 km)(0.500) 5 20.0 km<br />

B y<br />

5 B sin 60.0° 5 (40.0 km)(0.866) 5 34.6 km<br />

R x<br />

5 A x<br />

1 B x<br />

5 17.7 km 1 20.0 km 5 37.7 km<br />

R y<br />

5 A y<br />

1 B y<br />

5 217.7 km 1 34.6 km 5 16.9 km<br />

R 5 "R x 2 1 R y 2 5 "137.7 km2 2 1 116.9 km2 2 5 41.3 km<br />

u5tan 21 16.9 km<br />

a<br />

37.7 km b 5 24.1° (Continued)<br />

REMARKS Figure 3.12b shows a sketch of the components of R S and their directions in space. The magnitude and direction<br />

of the resultant can also be determined from such a sketch.<br />

Copyright 2010 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).<br />

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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