1

1
3
1 2
t 4 t
2
3 1
t 4 t
4
t
= t
3
1
4 4
2
a
1
3
2c4b2
7a3d3
Example 2: Simplify the following
Solution
(i)
(ii)
(i)
27
(ii)
8
27
1
3
81
16
3
4
1
1
8 3
3
27
8
81
16
3
2
3
4
4
8
1
27
1
3
3
4
3
4
4
27
8
1
3
1
3
81
16
3
2
3
4
3
4
3
4
4
3
4
4
Example 3: Simplify:(i)
3
2
3
1
3
1
3
3
3
2
3
3
3
2
1
b2
7 d3
c4
1
3
3
1
3
3
27
8
7
4 3
2 5
x
yz x
yz
xz 2
2n1
n1
32
42
(ii)
Solution:
2
n1
2
n
7
4 3
2 5
(i) x
yz x
yz
xz 2
4 3
2
5
x yz x yz
=
7
xz 2
1
2
3
2
5
1 1
8 2 6
x y z
x 2 y 2 z 2
= 7 7
x 2 z 2
5 1 1
8
2
6
2 2 2
=
x
y
x
7
2
z
z
7
2
5 1 1 7 7
8 2
6
=
x 2 y 2 z 2
x 2 z 2
5 7
5
1 7
8
6
=
x 2 2
y 2
z 2 2
=
x
5
2 2 9
y
z
n1
n1
32
42
(ii)
2
n1
Example 4:
Solution:
3 2
=
x x 3
x
x
1
3
x
2 1
3 3
x
1
1
2
2
n
n 1
3
2
2 4
2
2
n n
2
2 2
n
6
2 2
2
2
2 2
=
n n
2
=
2
n
n
Simplify:
=
1
=
x
2
3
x
x
6 2
2 1
x
1
2
1
3
n
4
1
3
2
x x 3
=
x
x 1
x 1
23
=
5
6 x 6
x
3
1
6
x
x
2
3
x
5
5
x 2 xy
Example 5: Simplify
3
xy y
1
2
x
1
1
3
x
x y
n