J4
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N<br />
A<br />
B<br />
15km<br />
S<br />
75 0<br />
A<br />
Then we choose a suitable scale to draw an accurate scale drawing.<br />
Use the scale of 1 cm represents 3 km. The accurate scale drawing<br />
is shown below.<br />
N<br />
A<br />
B<br />
75 0<br />
5cm<br />
x<br />
S<br />
A<br />
(a)<br />
To calculate the bearing of A from B, consider line AB as a transversal of two<br />
parallel lines passing through A and B respectively. The bearing of A from B is<br />
greater than 180 0 . The angle indicated as x is alternate to the angle marked at A,<br />
which is 75 0 . Therefore x = 75 0 .<br />
Therefore the bearing of A from B is 180 0 + 75 0 = 255 0 .<br />
Example<br />
Village P is 25 km due east of village Q. Village R is 20 km from Q on a bearing of S 45 0<br />
W.<br />
(a) Find the distance between R and P.<br />
(b) Find the bearing of R from P.<br />
Solution<br />
We draw a sketch first.<br />
N<br />
A<br />
N<br />
A<br />
Q<br />
N<br />
45 0<br />
25km<br />
P<br />
B<br />
R S<br />
S<br />
A<br />
We use a scale of 1 cm represents 5 km in making an accurate scale drawing.