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N<br />

A<br />

B<br />

15km<br />

S<br />

75 0<br />

A<br />

Then we choose a suitable scale to draw an accurate scale drawing.<br />

Use the scale of 1 cm represents 3 km. The accurate scale drawing<br />

is shown below.<br />

N<br />

A<br />

B<br />

75 0<br />

5cm<br />

x<br />

S<br />

A<br />

(a)<br />

To calculate the bearing of A from B, consider line AB as a transversal of two<br />

parallel lines passing through A and B respectively. The bearing of A from B is<br />

greater than 180 0 . The angle indicated as x is alternate to the angle marked at A,<br />

which is 75 0 . Therefore x = 75 0 .<br />

Therefore the bearing of A from B is 180 0 + 75 0 = 255 0 .<br />

Example<br />

Village P is 25 km due east of village Q. Village R is 20 km from Q on a bearing of S 45 0<br />

W.<br />

(a) Find the distance between R and P.<br />

(b) Find the bearing of R from P.<br />

Solution<br />

We draw a sketch first.<br />

N<br />

A<br />

N<br />

A<br />

Q<br />

N<br />

45 0<br />

25km<br />

P<br />

B<br />

R S<br />

S<br />

A<br />

We use a scale of 1 cm represents 5 km in making an accurate scale drawing.

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