20.07.2017 Views

J4

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

N<br />

A<br />

N<br />

A<br />

Q<br />

N<br />

45 0<br />

5cm<br />

P<br />

B<br />

4cm<br />

40 0 135 0<br />

R<br />

(a) Measuring from the scale drawing, the distance between R and P is about 8.3 5 =<br />

41.5 km.<br />

(b) To find the bearing of R from P, we draw a perpendicular through P and indicate<br />

North (N) and South (S). Then we measure the angle between PR and the line NS. This<br />

angle is about 70 0 . Therefore, the bearing is S 70 0 W<br />

or 180 0 + 70 0 = 250 0 .<br />

Example<br />

S<br />

A<br />

S<br />

Starting from a point A, I walk 40m on a bearing of 040 0 . Then I turn and walk a further<br />

30m on a bearing of 135 0 to a point B.<br />

(a) What is the bearing of B from A?<br />

(b) How far is it from A to B?<br />

Solution<br />

N<br />

N<br />

A<br />

B<br />

First we draw a rough sketch:<br />

Choose a suitable scale: 1cm = 10m<br />

- Draw the north line from the starting point.<br />

- Measure the bearing from the north line. Draw the line 4cm = 40m<br />

- Draw a new north line at the next turning point. It must be parallel to the first north<br />

line. Measure the turn to a bearing of 135 0 to the point B. Draw the line 3cm =<br />

30m (use a ruler and set square to draw the parallel lines)<br />

- We draw the line joining A to B. Measure angle NAB = 79 0 . Therefore the bearing<br />

of B from A = 079 0 .

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!