Almost-all results on the p^\lambda problem
Almost-all results on the p^\lambda problem
Almost-all results on the p^\lambda problem
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
provided <strong>the</strong> c<strong>on</strong>diti<strong>on</strong> (10) is satisfied.<br />
We are now in a positi<strong>on</strong> to prove<br />
Lemma 10: For every sufficiently sm<str<strong>on</strong>g>all</str<strong>on</strong>g> fixed η > 0 we have (11) when<br />
N t+100η ≤ Y,<br />
provided <strong>the</strong> c<strong>on</strong>diti<strong>on</strong>s in (9) and (10) as well as <strong>the</strong> c<strong>on</strong>diti<strong>on</strong>s<br />
are satisfied.<br />
t < (2 − λ)/5, t < (14 + 5λ)/54, t < (14 − 9λ)/32 (12)<br />
Proof: We first note that <strong>the</strong> sum �<br />
same manner as �<br />
h≤H<br />
h≤H<br />
|Kh| 2 can alternatively be estimated in <strong>the</strong><br />
|Lh| 2 was estimated in Lemma 6. Thus, we also have (11) when<br />
N t+100η ≤ Y ≤ N 2−λ−4t−100η ,<br />
provided <strong>the</strong> c<strong>on</strong>diti<strong>on</strong>s in (9) are satisfied. By this observati<strong>on</strong> and Lemma 9, for proving<br />
Lemma 10 it suffices to show that<br />
and<br />
(λ + 2t)/2 < min{1 − t, 7(1 + λ)/9 − 2t} (13)<br />
max{(11λ + 36t)/7 − 2, t} < 2 − λ − 4t. (14)<br />
Indeed, (13) follows from <strong>the</strong> first and <strong>the</strong> sec<strong>on</strong>d c<strong>on</strong>diti<strong>on</strong> in (12), and (14) follows<br />
from <strong>the</strong> first and <strong>the</strong> third c<strong>on</strong>diti<strong>on</strong> in (12). This completes <strong>the</strong> proof. ✷<br />
5 Proof of Theorem 4<br />
We suppose that 1/2 ≤ λ < 1 and<br />
We choose t in such a manner that<br />
and we take<br />
0 ≤ τ < min{(2 − λ)/6, (14 − 9λ)/32}.<br />
max{τ, 2(1 − λ)/5} < t < min{(2 − λ)/6, (14 − 9λ)/32},<br />
u := N t+100η ,<br />
v := N 2−λ−4t−100η ,<br />
z := N t+100η .<br />
8