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<strong>ACSM</strong> <strong>Metabolic</strong> <strong>Equations</strong><br />

(HPRED 1410, Dr Bailey, Appendix D, Guidelines)<br />

<strong>ACSM</strong> metabolic equations are typically used for two purposes:<br />

1. To calculate oxygen consumption and from this, the energy expenditure<br />

of a given exercise.<br />

2. To calculate the target workload for a client on the specific mode used.<br />

Note that each equation will have the following components:<br />

VO2 = horizontal component + vertical component + resting component<br />

Walking<br />

Walking: VO2 = H + V + R<br />

Walking: VO2 = 0.1(speed) + 1.8 (speed) (fractional grade) + 3.5<br />

0.1 ml x kg -1 x min -1 = O2 cost of horizontal movement<br />

1.8 ml x kg -1 x min -1 = O2 cost of vertical ascent<br />

Speed = speed in m x min -1<br />

Running<br />

Running: VO2 = H + V + R<br />

Running: VO2 = 0.2 (speed) + 0.9 (speed)(fractional grade) + 3.5<br />

0.2 ml x kg -1 x min -1 = O2 cost of horizontal motion<br />

0.9 ml x kg -1 x min -1 = O2 cost of vertical ascent cost<br />

1


Stepping<br />

Stepping: VO2 = H + V + R<br />

Stepping: VO2 = 0.2 (stepping rate) +1.33 x 1.8 (step height)(step freq) +3.5<br />

= 0.2 (stepping rate) + 2.4 (step height)(step freq) +3.5<br />

1.8 ml x kg -1 x min -1 = O2 cost of vertical ascent<br />

1.33 = O2 cost of stepping down (vertical descent)<br />

(1.33 includes the positive component of stepping up (1.0), and the negative<br />

component of stepping down. (0.3)<br />

step height = step height in meters, step freq = stepping frequency in min -1<br />

Leg and Arm Ergometry<br />

Note that there is no horizontal or vertical component here. All we see is the<br />

resistive component (V) from the ergometer.<br />

Leg Ergometry<br />

Leg Ergometry: VO2 = V (resistive) + R<br />

Note: 1. There is no horizontal component in leg ergometry<br />

2. The vertical component is actually a resistive component.<br />

Leg Ergometry: VO2 = (10.8 x W x M -1 ) + 7<br />

Use (mathematically equivalent); VO2 = 1.8 (work rate)/body mass + 7<br />

1.8 ml x kg -1 x min -1 = cost of cycling against external load<br />

3.5 ml x kg -1 x min -1 = cost of unloaded cycling above and<br />

beyond resting metabolism, so “7” is 3.5 + 3.5.<br />

W = watts, M = mass in Kgs<br />

2


Arm Ergometry<br />

Arm Ergometry: VO2 = V (resistive) + R<br />

Arm Ergometry: VO2 = (18 x W x M -1 ) + 3.5<br />

Use (mathematically equivalent); VO2 = 3 (work rate)/body mass + 3.5<br />

Note: 1. There is no horizontal component in leg ergometry<br />

2. The vertical component is actually a resistive component.<br />

3. In arm ergometry, arm muscle mass is so small that there is<br />

no term for unloaded cyling. Hence, no “7” is seen.<br />

Also needed for arm and leg ergometry:<br />

Power (Kg x m x min -1 ) = (Kg setting)(D)(pedaling cadence in rpm)<br />

D = 6 meters for Monark<br />

= 3 meters for Tunturi<br />

= 2.4 for Monark arm ergometer<br />

Stepwise Approach to <strong>Metabolic</strong> Calculation<br />

1. Conversion to appropriate units and knowledge of common<br />

equivalents.<br />

A. Convert all weights from pounds (lbs) to kilgrams.<br />

* Pounds/2.2 = kilograms<br />

B. Convert speed from miles per hour (m/hr) to meters per minute<br />

(m/min).<br />

* miles/hr x 26.8 = meters/minute<br />

* (also useful; 60/(min/mile) = miles per hour<br />

C. Common equivalents<br />

* (Caloric expenditure in kcals x min -1 )/5 = VO2 in L x min -1<br />

* Liters O2 x 5 kcals/liter O2 = kcals<br />

* 1 pound of fat = 3,500 kcals<br />

* METs x 3.5 m x kg -1 x min -1 = VO2 in ml x kg -1 x min -1<br />

* Gross VO2 in ml x kg -1 x min -1 / 3.5 = METs<br />

* Power in watts x 6 = workload in kg x m x min -1<br />

* (kgm/min)/6 = watts<br />

3


2. Transform VO2 into the most appropriate units.<br />

A. If weight bearing; walking, running, stepping, use ml x kg -1 x min -1<br />

B. If cycling or arm, use ml/min<br />

C. If caloric expenditure needed, convert from ml x kg -1 x min -1 to<br />

liters/minute<br />

3. Choose the proper equation for gross VO2:<br />

Walking: VO2 = 0.1(speed) + 1.8 (speed) (fractional grade) + 3.5<br />

Running: VO2 = 0.2 (speed) + 0.9 (speed)(fractional grade) + 3.5<br />

Stepping: VO2 = 0.2 (step rate) +1.33 x 1.8 (step height)(step rate) +3.5<br />

(step height in meters, where 1 inch =.0254 m)<br />

Leg Ergometry: VO2 = 1.8 (work rate)/body mass + 7<br />

Arm Ergometry VO2 = 3 (work rate)/body mass + 3.5<br />

Power (Kg x m x min -1 ) = (Kg setting)(D)(pedaling cadence in rpm)<br />

Example from <strong>ACSM</strong> Guidelines<br />

1. 30 year old man: He wants to walk at 3.5 mph<br />

* 180 lbs<br />

* RHR of 60<br />

* MHR of 190<br />

* VO2 max 48 ml/kg/min.. You want him at 70 % of his VO2 R<br />

A. What is his minimum training heart rate by the Karvonen method?<br />

THR = (.70)(190 - 60) + 60<br />

THR = 91 + 60 = 151 beats/min<br />

B. What is his target VO2?<br />

VO2R = 48 ml/kg/min – 3.5 ml/kg/min = 44.5 = net VO2<br />

= .70 x 44.5 = 31.2 ml/kg/min<br />

4


C. How steep should the treadmill be if he is walking at his preferred<br />

3.5 mph?<br />

VO2 = 0.1 (speed) + 1.8 (speed)(fractional grade) + 3.5 ml/kg/min<br />

31.2 = 0.1 (93.8) + 1.8 (93.8) (frac grade) + 3.5 ml/kg/min<br />

27.7 = 0.1 (93.8) + 1.8 (93.8)(frac grade)<br />

27.7 = 9.38 + 168.8 (frac grade)<br />

18.3 = 168.8 (frac grade)<br />

fractional grade = 10.8 %<br />

D. What is his target work rate on the Monark bike?<br />

His body mass = 180 lbs/2.2 = 81.8 kg<br />

VO2 = 7.0 +1.8 (work rate)/body mass<br />

VO2 = 7.0 +1.8 (work rate)/81.8<br />

31.2 = 7.0 + 1.8 (work rate)/81.8<br />

24.2 = 1.8 (work rate)/81.8<br />

1980 = 1.8 (work rate)<br />

work rate = 1100 kg x m -1 x min -1<br />

E. If he wants to pedal at 60 rpm on a Monark cycle, what resistance<br />

setting should be used.<br />

Power (Kg x m x min -1 ) = (Kg setting)(D)(pedaling cadence in rpm)<br />

Work rate = (resistance setting)(D)(pedal cadence)<br />

1100 = (resistance setting)(6)(60)<br />

1100 = (resistance setting)360<br />

Resistance setting = 3.05 kg<br />

F. What is the caloric expenditure during 30 minutes of exercise?<br />

Net VO2 = 31.2 ml/kg/min<br />

(VO2 in ml/kg/min)(body mass)/1000 = VO2 L/min<br />

(31.2)(81.8)/1000 = 2.55 L/min<br />

2.55 L/min x 5 = 12.8 kcal/min<br />

12.8 kcal/min x 30 = 383 kcals<br />

5


Text examples, page 311, Guidelines<br />

HPRED 1410, Feb 23, 2004<br />

1. A man weighing 176 lbs runs a pace of 9 minutes per mile outdoors, on<br />

level ground. What is his estimated gross VO2 ?<br />

Conversion to appropriate units and knowledge of common<br />

equivalents.<br />

S = 9 minutes/mile, to convert to m x min -1 ,<br />

1. mph = 60 � min/mile = mph<br />

= 60/9 = 6.66<br />

2. m x min-1 = 6.66 x 26.8 = 178.5<br />

Choose the proper equation for gross VO2: Running:<br />

VO2 = 0.2 (speed) + 0.9 (speed)(fractional grade) + 3.5<br />

VO2 = (0.2 x 178.5 m x min -1 ) + 0 + 3.5<br />

VO2 = 35.7 + 0 + 3.5 = 39.2 ml x kg -1 x min -1<br />

2. To match this exercise intensity (from above) on a Tunturi cycle<br />

ergometer, what setting would you use at a pedal rate of 60 rpm?<br />

Conversion to appropriate units and knowledge of common<br />

equivalents.<br />

176lbs/2.2 = 80 kgs<br />

Choose the proper equation for gross VO2: Leg Ergometry:<br />

VO2 = 1.8 (work rate)/mass + 7<br />

39.2 ml x kg -1 x min -1 = (1.8 x W)/80 + 7<br />

32.2 = 1.8W/80<br />

1431 kg m min = work rate<br />

6


Power (Kg x m x min -1 ) = (Kg setting)(D)(pedaling cadence in rpm)<br />

1431 = Kg (3)(60)<br />

Kg = 7.95<br />

3. If this same man exercised at this intensity 5 times a week for 30<br />

minutes each session, how long would it take him to lose 12 pounds?<br />

(20) p. 311 top<br />

Net VO2 = 39.2 -3.5 = 35.7<br />

Liter of oxygen used =<br />

35.7 ml x kg -1 x min -1 x 80 kg/1000 = 2.856 L/min O2<br />

Kcals used per minute =<br />

2.856 L/min x 5 kcals/Liter O2 = 14.28 kcals<br />

Kcals per session = 14.28 kcals/min x 30 minutes = 428.4 kcals<br />

Kcals/week = 5 times/wk x 428.4 = 2142 kcals/wk<br />

Total Kcals to lose = 12 lbs x 3500 kcals/lb = 42000 kcals<br />

Weeks to lose it = 42000kcals/2142 kcals/week = 19.6 weeks<br />

4. For a desired training intensity of 75 % of the VO2res, at what heart rate<br />

should a 45 year old woman exercise ? Her resting heart rate is 70 beats<br />

a minute.<br />

MHR = 220 - 45 = 175<br />

HRR = 175- 70 = 105<br />

.75 x 105 = 78.75<br />

78.75 + 70 = 149<br />

5. A 198 pound cardiac patient wishes to use an arm ergometer for part of<br />

his rehabilitation program. He works at a power output of 300<br />

kgxmxmin for 15 minutes and then at 450 kgxmxmin for 15 minutes.<br />

What is his average net VO2 (in ml x kg -1 x min -1 ) over this session?<br />

198/2.2 = 90 kgs<br />

7


Arm Ergometry VO2 = 3 (work rate)/body mass + 3.5<br />

First 15 minutes; VO2 = 3 (300)/90 + 3.5<br />

Gross VO2 = 900/90 +3.5 = 13.5 ml x kg -1 x min -1<br />

Net VO2 = 13.5 –3.5 = 10 ml x kg -1 x min -1<br />

15 minutes x 10.0 = 150.0 ml x kg -1 x min -1<br />

Second 15 minutes: VO2 = 3 (work rate)/body mass + 3.5<br />

Gross VO2 = 3(450)/90 + 3.5 = 18.5 ml x kg -1 x min -1<br />

Net VO2 = 18.5 – 3.5 = 15 ml x kg -1 x min -1<br />

15 minutes x 15.0 = 225.0 ml x kg -1 x min -1<br />

Average net= (150 + 225)/30 = 12.5 ml x kg -1 x min -1<br />

6. If an individual reduces his or her dietary intake by 1750 kcal per week,<br />

how much weight (in lbs) would he or she lose in 6 months (26 weeks)?<br />

Weight lost per week = 1750/3500 = .5 pounds<br />

26 x .5 = 13 pounds<br />

7. If an 18 year old girl steps up and down on a 12 inch step at a rate of 20<br />

steps (complete up and down cycles) per minute, what would her gross<br />

VO2 be (in ml x kg -1 x min -1 ) ?<br />

Stepping:<br />

Gross VO2 = 0.2 (step rate) +1.33 x 1.8 (step height)(step rate) +3.5<br />

= 0.2(20) + 1.33 x 1.8 (12)(20) + 3.5<br />

1 inch = 0.0254 meters<br />

step height in meters = 12 x .0254 = .3048<br />

8


VO2 = 0.2(20) + 1.33 x 1.8 (.3048)(20) + 3.5<br />

= 4 + 14.59 + 3.5 = 22.09 ml x kg -1 x min -1<br />

8. A 71-year-old man weighing 180 pounds walks on a motor-driven<br />

treadmill at 3.5 mph and a 15 % grade. What is his gross MET level?<br />

Walking: VO2 = 0.1(speed) + 1.8 (speed) (fractional grade) + 3.5<br />

3.5 mph x 26.8 = 93.8 m/min<br />

VO2 = 0.1(speed) + 1.8 (speed) (fractional grade) + 3.5<br />

= 0.1(93.8) + 1.8(93.8)(.15) + 3.5<br />

= 9.38 + 25.33 + 3.5 = 38.2 ml x kg -1 x min -1<br />

Gross MET level = 38.2/3.5 = 10.9 METs<br />

9


Case Study 1:<br />

Case Studies for HPRED 1410<br />

70 kg man uses 2 liters of oxygen in one minute.<br />

A. How many calories did he burn?<br />

B. What was his exercise in METs?<br />

Case Study 2: A man with the following information will burn how many<br />

kcals each exercise session while running?<br />

Treadmill at 1 % grade<br />

Speed = 6.5 mph<br />

Time = 30 minutes<br />

5 times a week<br />

Body weight = 175 pounds<br />

= 79.5 kg<br />

Case Study 3: If the same man walks for 30 minutes per session, how many<br />

calories per session will he burn?<br />

Treadmill at 4 % grade<br />

Speed = 4.4 mph<br />

Time = 30 minutes<br />

5 times a week<br />

Body weight = 175 pounds<br />

Case Study 4: 38 year old male, resting heart rate = 60, body weight of 170<br />

pounds, percent body fat = 18%<br />

1. Calculate his training heart rate range from 60 to 75 % of the heart rate<br />

reserve.<br />

2. How many weeks would it take him to reduce his body weight to 12 %<br />

body fat if he adhered to a proper program?<br />

10


Case Study 5: A 25 year old woman who weighs 130 pounds has a<br />

predicted VO2 max of 40 ml x kg -1 x min -1 . You decide that you want her to<br />

exercise (run) at 60 % of her VO2 R.<br />

1. How fast should you set the treadmill speed in miles per hour assuming<br />

zero percent grade?<br />

2. If she runs for 40 minutes, 4 days per week, how many calories wills she<br />

burn?<br />

3. At this rate, many weeks would it take her to burn 10 pounds through<br />

this exercise?<br />

Case Study 6: A 24 year old male client tells you that during his last<br />

treadmill run, he measured his heart rate at 145 beats per minute. He tells<br />

you that his resting heart rate is 60. He wants to know “how intense” you, as<br />

an exercise physiologist, think this is.<br />

What percentage of the heart rate reserve (% VO2R ) was he running at?<br />

Case Study 7: You measure a 48 year old man’s VO2 max to be 30 ml x kg -<br />

1 x min –1 . He tells you that he wants to begin shoveling snow from his<br />

driveway from now on for exercise, instead of hiring a local kid. According<br />

to the <strong>ACSM</strong> RM, heavy shoveling is about 9 MET exertion. What would<br />

you advise him?<br />

Your advice:<br />

11


Case Study Solutions for <strong>ACSM</strong> Guidelines Problems<br />

Case Study 1:<br />

70 kg man uses 2 liters of oxygen in one minute.<br />

A. How many calories did he burn?<br />

2 liters x 5 kcals/liter = 10 kcals<br />

B. What was his exercise in METs?<br />

1. 2 liters of oxygen = 2000 millilters of oxygen<br />

2. 2000/70 kg = 28.6 ml/Kg oxygen in one minute<br />

3. MET level = 28.6 ml x kg -1 x min -1 / 3.5 ml/kg/min= 8 METs<br />

4. This is a light jog pace.<br />

Case Study 2: A man with the following information will burn how many<br />

kcals each exercise session while running?<br />

Treadmill at 1 % grade<br />

Speed = 6.5 mph<br />

Time = 30 minutes<br />

5 times a week<br />

Body weight = 175 pounds<br />

= 79.5 kg<br />

Running: Gross VO2 = 0.2 (speed) + 0.9 (speed)(fractional grade) + 3.5<br />

First you need speed in m/min: 6.5 mph x 26.8 = 174.2 m/min<br />

Gross VO2 = 0.2 (174.2) + 0.9 (174.2)(.01) + 3.5<br />

= 34.84 + 1.57 + 3.5 = 39.9 ml x kg -1 x min -1<br />

Net VO2 = 39.9 –3.5 = 36.4 ml x kg -1 x min -1<br />

Liters/minute = (36.4 x 79.5)/1000 = 2.895 Liters/min<br />

2.895 x 5 kcals/liter = 14.5 kcals/minute<br />

12


30 x 14.5 = 434.3 kcals<br />

Case Study 3: If the same man walks for 30 minutes per session, how many<br />

calories per session will he burn?<br />

Treadmill at 4 % grade<br />

Speed = 4.4 mph<br />

Time = 30 minutes<br />

5 times a week<br />

Body weight = 175 pounds<br />

Walking: Gross VO2 = 0.1(speed) + 1.8(speed)(fractional grade) + 3.5<br />

4.4 mph x 26.8 = 117.92 m/min<br />

Gross VO2 = 0.1(117.92) + 1.8(117.92)(.04) + 3.5<br />

11.79 + 8.49 + 3.5 = 23.7 ml x kg -1 x min –1<br />

Net VO2 = 23.7 –3.5 = 20.2 ml x kg -1 x min -1<br />

Liters/minute = (20.2 x 79.5)/1000 = 1.6 Liters/min<br />

1.6 x 5 = 8 kcals/minute, 30 x 8 = 240 kcals<br />

Case Study 4: 38 year old male, resting heart rate = 60, body weight of 170<br />

pounds, percent body fat = 18%<br />

1. Calculate his training heart rate range from 60 to 75 % of the heart rate<br />

reserve.<br />

Minimum THR = (182 - 60) x .60 + 60 = 133.2<br />

Maximum THR = (182 - 60) x .75 + 60 = 151.5<br />

2. How many weeks would it take him to reduce his body weight to 12 %<br />

body fat if he adhered to a proper program?<br />

13


Case Study 5: A 25 year old woman who weighs 130 pounds has a<br />

predicted VO2 max of 40 ml x kg -1 x min -1 . You decide that you want her to<br />

exercise (run) at 60 % of her VO2 R.<br />

1. How fast should you set the treadmill speed in miles per hour assuming<br />

zero percent grade?<br />

VO2 R: 40 ml/kg/min – 3.5 ml/kg/min = 36.5 ml/kg/min<br />

Running: VO2 = 0.2 (speed) + 0.9 (speed)(fractional grade) + 3.5<br />

Target VO2 = .60 x 36.5 ml x kg -1 x min –1 = 24 ml x kg -1 x min –1 .<br />

21.9 = 0.2 (speed) + 0.9 (speed)(0) + 3.5<br />

21.9 = 0.2 (speed) + 3.5<br />

18.4 = 0.2 (speed)<br />

Speed = 92 meters/min<br />

miles/hr x 26.8 = meters/minute<br />

miles/hr x 26.8 = 92 meters/minute<br />

Speed in mph for the treadmill = 92/26.8 = 3.4 mph<br />

(Note: You might find that this client will prefer to walk and need to<br />

recalculate.)<br />

2. If she runs for 40 minutes, 4 days per week, how many calories wills she<br />

burn?<br />

Weight in Kgs = 130/2.2 = 59.1 kgs<br />

Net VO2 = 24 -3.5 = 20.5 ml x kg -1 x min –1<br />

(20.5 ml x kg -1 x min –1 x 59.1)/1000 = 1.211 Liters/O2 per minute<br />

Kcals burned per minute = 1.211 x 5 kcals/liter O2 = 6.06 kcals<br />

Kcals burned per session = 6.06 x 40 minutes = 242.31 kcals<br />

Kcals burned per wk = 242.31 kcals x 4 days/week = 969.2 kcals/week<br />

14


3. At this rate, many weeks would it take her to burn 10 pounds through<br />

this exercise?<br />

10 pounds x 3,500 kcals/pound = 35,000 kcals<br />

35,000/969.2 = 36.1 weeks<br />

Case Study 6: A 24 year old male client tells you that during his last<br />

treadmill run, he measured his heart rate at 145 beats per minute. He tells<br />

you that his resting heart rate is 60. He wants to know “how intense” you, as<br />

an exercise physiologist, thinks this is.<br />

What percentage of the heart rate reserve (% VO2R ) was he running at?<br />

% VO2R = (Exercise HR - Resting HR)/(Max HR - Resting HR)<br />

% HRR = (145 – 60)/(196-60)<br />

= 85/136 = 62.5 % HRR<br />

Case Study 7: You measure a 48 year old man’s VO2 max to be 30 ml x kg -<br />

1 x min –1 . He tells you that he wants to begin shoveling snow from his<br />

driveway from now on for exercise, instead of hiring a local kid. According<br />

to the <strong>ACSM</strong> RM, heavy shoveling is about 9 MET exertion. What would<br />

you advise him?<br />

Functional Capacity = 30/3.5 = 8.57 METs<br />

Your advice:<br />

This would often require supramaximal (above his VO2 max) exertion and he<br />

is 48 years old, at least “moderate risk”. Keep hiring the kid and begin a<br />

light supervised exercise program.<br />

15

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