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2. Damped Free Vibration SDOF

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EQ Eng, Fall 2005 HW #2<br />

<strong>Damped</strong> <strong>SDOF</strong> <strong>Vibration</strong><br />

Answers<br />

1. Text, Problem 2-1. ξ = 0.0529<br />

K = 50.1 k/in<br />

c = 0.539 k-s/in<br />

<strong>2.</strong> Text, Problem 2-<strong>2.</strong>b<br />

v(<br />

1s)<br />

= −0.<br />

756in<br />

v�<br />

( 1s)<br />

= 1.<br />

118 in / s<br />

3. See below. T = 0.846s<br />

ξ = 0.0221<br />

Problem 3. Analyze the dynamic response of the water tower described below.<br />

a) Calculate the natural period (T) based on the following<br />

information.<br />

• the diameters are outside diameters<br />

• both the column and the tank are made of ½"-thick steel<br />

• unit weight of steel and water are 490pcf and 6<strong>2.</strong>4pcf,<br />

respectively. Assume the tank is completely full of water.<br />

• locate the center of mass (cm) of the water tower at the<br />

midpoint of the water tank. Include half of the mass of the<br />

column.<br />

• Use the deflections in the attached chart to calculate the lateral<br />

stiffness of the water tower (PH / ∆Η at the cm).<br />

b) Calculate the damping ratio (ξ) using the logarithmic decrement<br />

method and the following information. The tower is pulled back<br />

6" and released from rest. Five vibration cycles later the<br />

displacement = 3".<br />

c) Make a "movie" showing the forces on the center of<br />

mass of the water tower by drawing nine free-body<br />

diagrams (like the one at right) at t = 0, t = TD/8, t =<br />

2TD/8, t = 3 TD/8, … , t = TD. Indicate the relative<br />

position of the center of mass to the displacement at t =<br />

0 (vmax).<br />

Initial displacement = 24"<br />

Initial velocity = 0"/s<br />

vmax<br />

0.71vmax<br />

40'<br />

T = TD / 8<br />

30'<br />

10'<br />

Plan View<br />

Elevation View<br />

Fc = 100 k<br />

Fk = 2319 k<br />

20'<br />

2219 k = -ma

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