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analysis of transient heat conduction in different geometries - ethesis ...

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Thus,<br />

a 1 = 0<br />

(3.86)<br />

Apply<strong>in</strong>g second boundary condition we have<br />

Thus,<br />

a + 2a<br />

=−Bθ<br />

1 2<br />

a<br />

2<br />

Bθ<br />

=−<br />

2<br />

We can also write the second boundary condition as<br />

Us<strong>in</strong>g equation (3.86), (3.83) and (3.88-3.89) we have<br />

Average temperature is expressed as<br />

Substitut<strong>in</strong>g the value <strong>of</strong> θ and m we have<br />

Integrat<strong>in</strong>g the equation (3.91) we have<br />

33<br />

(3.87)<br />

(3.88)<br />

∂ θ<br />

=− B( a0 + a1+ a2)<br />

∂ x<br />

(3.89)<br />

⎛ B ⎞<br />

a0 = θ ⎜1+ ⎟<br />

⎝ 2 ⎠ (3.90)<br />

( ) 1<br />

1<br />

θ = + ∫ θ<br />

m<br />

m x dx<br />

0<br />

2 3<br />

( 0 1 2 )<br />

1<br />

∫ 0<br />

(3.91)<br />

θ = 2 ax+ ax + ax dx<br />

Substitut<strong>in</strong>g the value <strong>of</strong> 0 a , 1 a and 2 a we have<br />

⎛a0a1 a2<br />

⎞<br />

θ = 2⎜ + + ⎟<br />

⎝ 2 3 4 ⎠ (3.92)<br />

⎛ B ⎞<br />

θ = θ⎜1+ ⎟<br />

⎝ 4 ⎠ (3.93)

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