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Fuerzas internas

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7.4 CablesCable sujeto a su propio peso• Resultadsdx = { 1+ 1 (∫ w(2s)ds) 2 }1 /2F H• Separando las variables e integrandox=∫ds{11+2 (∫ w (s)ds ) 2 }1/2F H

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