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BAB 4. INTEGRAL LIPAT DUA - Blog

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Atau<br />

R<br />

1 2<br />

1 1 2<br />

= y − y = −1.<br />

2 2<br />

1 2<br />

( x − y)<br />

dA = ( x − y)<br />

dydx = xy − y dx<br />

2<br />

0 0<br />

1<br />

1<br />

0<br />

1<br />

1 2<br />

= x . 2 − . 2 dx<br />

2<br />

0<br />

= ( x − 2)<br />

0<br />

2 dx<br />

2<br />

= [ − x]<br />

= −1<br />

2 1<br />

0<br />

2<br />

0<br />

x .<br />

Terlihat dengan urutan intergral berbeda diperoleh hasil yang sama.<br />

b d<br />

Pada kasus f ( x, y) = g ( x) h( y)<br />

, maka ( ) ( ) = ( ) ( )<br />

, dengan R = [ a b] × [ c d ]<br />

, , .<br />

R<br />

2<br />

0<br />

g x h y dA g x dx h y dy<br />

a c<br />

π π<br />

Contoh <strong>4.</strong>3 : Jika R = 0, × 0, , tentukan sin xcos y dA.<br />

2 2<br />

Penyelesaian:<br />

Teorema Fubini untuk daerah sembarang<br />

Ada dua tipe , seperti pada dua gambar berikut:<br />

R<br />

69

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