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GNE114 - Nota de Aula 04.1

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Exemplo<br />

Encontre vs para o circuito :<br />

V s = v r + v c + v l<br />

Vr = ( 0,234.sen (3000t – 10 0 ) ) . 270 = 63,2.sen ( 3000.t – 10 0 ).V<br />

Vl : wl = 3000.(120 – 10 -3 ) = 360 Ω<br />

Vl = ( 0,234.sen ( 3000.t –10 0 + 90 o ) ).360 = 84,2.sen ( 3000.t + 80 o ).V<br />

Vc :<br />

vs<br />

+<br />

-<br />

1<br />

=<br />

w. c<br />

1<br />

3000.<br />

6x10<br />

−6<br />

= 55,6 Ω<br />

Vc = ( 0,234.sen ( 3000.t –10 o – 90 o ) ) .55,6 = 13.sen . ( 3000.t –100 o ).V<br />

Vs = Vr + Vl + Vc = 63 -10 o + 84,2 80 o<br />

62,04 – j10,94 + 14,62 + j82,92 + ( - 2,25 ) + j ( -12,80 )<br />

74,41 + j59,17<br />

Vs = 95 38 o<br />

270 Ω<br />

+ -<br />

v r<br />

Vs = 95.sen ( 3000.t + 38 o ).V<br />

0,234.sen(3000t – 10 0 )<br />

120mH<br />

+ -<br />

v l<br />

+ 13 -100 o<br />

vc<br />

+<br />

-<br />

6 µ F

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