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Structura moleculară

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÷ ecuaţie: R +R ↔ R* + R → P<br />

÷ reacţii parţiale:<br />

o R + R → R* + R, v = k [ R]<br />

( 1)<br />

o R* + R → R + R, = k [ R][<br />

R*]<br />

v( 2)<br />

2<br />

v( 3)<br />

= 3<br />

o R* → P, k [ R *]<br />

÷ necunoscute:<br />

o [R] = x; [R*] = y; [P] = z;<br />

÷ conservarea masei:<br />

o (R):<br />

o (R*):<br />

x & = −v<br />

+ v<br />

( 1)<br />

( 1)<br />

( 2)<br />

y& = v − v − v<br />

( 2)<br />

o (P): z & = v(<br />

3)<br />

÷ ecuaţii diferenţiale:<br />

2<br />

2<br />

o & = −k<br />

x + k xy ; & = k x − k xy − k y ; & = k y<br />

x 1 2<br />

2<br />

x = −ax<br />

+<br />

( 3)<br />

1<br />

y 1 2 3<br />

2<br />

z 3<br />

o & 2<br />

bxy ; y&<br />

= ax − bxy − cy ; z&<br />

= cy<br />

÷ abordare greşită (căutarea unei soluţii analitice e fără succes):<br />

o<br />

2<br />

x + ax<br />

y =<br />

bx<br />

&<br />

2<br />

x&<br />

+ ax<br />

d( )<br />

2<br />

x & + ax<br />

; bx<br />

2<br />

2<br />

= ax − ( x&<br />

+ ax ) − c<br />

dt<br />

bx<br />

o<br />

2<br />

d(<br />

x&<br />

+ ax ) d(<br />

bx)<br />

2<br />

bx − ( x&<br />

+ ax )<br />

2<br />

dt dt<br />

x&<br />

+ ax<br />

= −x&<br />

− c<br />

2<br />

( bx)<br />

bx<br />

o<br />

2<br />

2 2<br />

2<br />

( &x<br />

& + 2axx&<br />

) bx − bx&<br />

( x&<br />

+ ax ) = −x&<br />

b x − c(<br />

x&<br />

+ ax ) bx<br />

o<br />

2 2 2<br />

2 2<br />

3<br />

bx&x & + 2abx<br />

x&<br />

− bx&<br />

− abx x&<br />

= −x&<br />

b x − bcx&<br />

− abcx<br />

o<br />

2 2 2 2<br />

3<br />

bx&x<br />

& + abx x&<br />

− bx&<br />

+ x&<br />

b x + bcx&<br />

+ abcx = 0<br />

o<br />

2 2 2<br />

3<br />

x&x<br />

& + ax x&<br />

− x&<br />

+ x&<br />

bx + cx&<br />

+ acx = 0<br />

o<br />

2 2<br />

2<br />

3<br />

x&<br />

− ax x&<br />

− x&<br />

bx − cx&<br />

− acx<br />

&x<br />

& =<br />

x<br />

o<br />

2<br />

2<br />

3<br />

dv dv v − ( a + b)<br />

x v − cv − acx<br />

v = x&<br />

; & x & = v ; v =<br />

dx dx<br />

x<br />

÷ abordare corectă (căutarea unei soluţii numerice):<br />

o model: R +R ↔ R* + R → P; [R] = x; [R*] = y; [P] = z;<br />

2 2<br />

o ecuaţii diferenţiale: x&<br />

= −ax<br />

+ bxy ; y&<br />

= ax − bxy − cy ; z&<br />

= cy<br />

o condiţii iniţiale: x(0)=R0; y(0)=0; z(0)=0;<br />

o iteraţii:<br />

x + ( −ax<br />

2<br />

+ bx y ) Δt<br />

xi = i−1<br />

i−1<br />

i−1<br />

i−1<br />

yi 2<br />

= yi<br />

−1<br />

+ ( axi<br />

−1<br />

− bxi<br />

−1yi<br />

−1<br />

− cy i−1<br />

zi = zi<br />

−1<br />

+ cyi−1Δ<br />

) Δt<br />

<br />

o aplicaţie numerică:<br />

t<br />

x = x + ( −ax<br />

2<br />

+ bx y ) Δt<br />

<br />

y<br />

i<br />

i<br />

i<br />

y = y<br />

z = z<br />

0<br />

a = 10<br />

i−1<br />

i−1<br />

i−1<br />

= 0; z<br />

−2<br />

+ ( ax<br />

+ cy<br />

0<br />

=<br />

2<br />

i−1<br />

i−1<br />

0; x<br />

; b = 10<br />

i−1<br />

Δt<br />

0<br />

−3<br />

− bx<br />

= R<br />

i−1<br />

0<br />

; c = 10<br />

i−1<br />

y<br />

−5<br />

i−1<br />

i−1<br />

− cy<br />

i−1<br />

= 1; Δt<br />

= 10<br />

) Δt<br />

-2<br />

8

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