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3)<br />
<br />
x<br />
<br />
<br />
( 0;7), a (1;2), b (3; 1),<br />
c <br />
(5;3)<br />
<br />
<br />
<br />
1<br />
2<br />
3 5 0<br />
1<br />
3 5 0<br />
<br />
<br />
1 3 7<br />
2a 1 0<br />
7 7 7:<br />
( 7)<br />
<br />
1<br />
3 5 0 <br />
<br />
K 3<br />
2t;<br />
1<br />
t;<br />
t,<br />
0<br />
1 1 1<br />
Pi volb t = 0 je x 1 = 3, x 2 = –1, x 3 = 0, takže:<br />
<br />
x<br />
x <br />
<br />
a , b,<br />
c<br />
<br />
3a<br />
b(<br />
0c)<br />
Vysvtlení: vektory a, b, c jsou LZ (jsou 3 a mají 2 souadnice),<br />
vektor x leží v téže rovin ešení musí být více.<br />
t<br />
<br />
R
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