ElektriÄne mreže 1 - FESB
ElektriÄne mreže 1 - FESB
ElektriÄne mreže 1 - FESB
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R<br />
⎛ U ⎞<br />
n<br />
⎜<br />
S<br />
⎟<br />
n<br />
=<br />
⎝ ⎠<br />
Z<br />
2<br />
⋅ P<br />
Jedinične impedancije transformatora (poprečne):<br />
⎛<br />
⎜<br />
2<br />
16 ⎞<br />
⎟ ⋅ 0,01⋅150<br />
150 ⎠<br />
1,71<br />
ks<br />
t<br />
=<br />
⎝<br />
=<br />
B<br />
2<br />
Rt<br />
Rt 1<br />
= = 0.005 p.<br />
u.<br />
2<br />
2<br />
0,01p.u.<br />
2 2<br />
Xt = Zt<br />
− R<br />
t<br />
= 0,11 − 0,01 = 0,11p.u.<br />
X<br />
R<br />
U<br />
P<br />
2<br />
n<br />
X<br />
X<br />
t<br />
2<br />
t1 = =<br />
0.055<br />
16 2<br />
0,0025⋅150<br />
1,71<br />
0<br />
m<br />
= =<br />
=<br />
Z<br />
B<br />
2<br />
2<br />
100 U<br />
n 100 16<br />
⋅ ⋅<br />
i0<br />
S<br />
n<br />
= =<br />
1 150<br />
Z 1,71<br />
m<br />
=<br />
B<br />
400 p.<br />
u.<br />
100 p.<br />
u.<br />
2. Proračun matrica impedancija vodova<br />
Udaljenosti vodiča:<br />
2<br />
2<br />
D12 = (3.7 + 4.7) + (17.5 − 15) = 8. 7641 m<br />
itd. D 13 =5.4231 [m] , D 32 =10.7935 [m] , D 1n =4.4654 [m] , D 2n =6.8622 [m] , D 3n =9.4810 [m]<br />
[ ]<br />
Jedinične impedancije (formule):<br />
r<br />
658 ρ<br />
Z<br />
ik z<br />
= 0.05<br />
+ j ⋅ 0.1445log (međusobne impedancije vodiča)<br />
−<br />
Dik<br />
f<br />
r<br />
658 ρ<br />
Z<br />
ii−<br />
z<br />
= R1 + 0.05 + j ⋅(0.1445 log + X<br />
u<br />
) (vlastita impedancija faznog vodiča)<br />
r f<br />
r<br />
658 ρ<br />
Z<br />
nn−<br />
z<br />
= R + 0.05 + j ⋅ (0.1445 log + X<br />
r f<br />
1 u<br />
n<br />
f<br />
) (vlastita impedancija zaštitnog vodiča)<br />
Proračun:<br />
r<br />
658 200<br />
Z11 − z<br />
= 0.08 + 0.05 + j ⋅(0.1445log<br />
+ 0.015) = 0.13+<br />
j0.7178<br />
0.018 50<br />
r<br />
658 200<br />
Z nn − z<br />
= 0.08<br />
+ 0.05 + j ⋅(0.1445log<br />
+ 0.015) = 0.13+<br />
j0.7433<br />
0.012 50<br />
r<br />
658 200<br />
Z12−<br />
z<br />
= 0.05 + j ⋅(0.1445log<br />
) = 0.05 + j0.3145<br />
8.7641 50<br />
r<br />
658 200<br />
Z13−<br />
z<br />
= 0.05 + j ⋅(0.1445log<br />
) = 0.05 + j0.3446<br />
8.4231 50<br />
r<br />
658 200<br />
Z1 n − z<br />
= 0.05 + j ⋅ (0.1445log<br />
) = 0.05 + j0.3568<br />
4.4654 50<br />
itd.<br />
29