THM 5 Gerinnehydraulik Technische Hydromechanik - Uni-Bremen

HTW Dresden, LG Wasserwesen, Prof. Dr.-Ing. T. GrischekLEHRMATERIAL THM 5 – GERINNEHYDRAULIKÜbungsaufgabe 5-1: Leistungsberechnunggeg.: H = 1,0 m ; b 0 = 2,0; Böschungsneigung 1 : 2 (m = 2); I E = 1%;Beton, glatth= 1,0mb o =2,0m1:2Hinweis: Für regelmäßigeQuerschnittsformen enthaltenTabellenwerke Formeln undTabellen für r hy , l u , A(1) Betongerinne Tabelle k St = ............ m 1/3 /s(2) A = h . b 0 + m . h 2 = ...............................................................l +2u= b0+ 2h 1 m = .........................................................r hy = A / l u = ...............................................(3) v = k . 2/3 .St r hy I 1/2 E = ...............................................................Q = A . v = ...............................................Übungsaufgabe 5-2: Ermittlung der Energieverlustegeg.: h = 1,0 m; b 0 = 2,0 m; m = 2; v = 5,80 m/s(1) k St = .......... m 1/3 /s(2) A = ........... m 2 ; l u = ......... m; r hy = ........... m s.o.(3) I E = ...........Übungsaufgabe 5-3: Ermittlung der Wassertiefegeg.: b 0 = 2,0 m, m = 2, k St = 80 m 1/3 /s, Q = 23,22 m 3 /s, I E = 1 %(1) Schätzung h * 1 = 0,6 m (rel. schlecht)*h 2 = ................. m(2) A 1 = ...................................... m 2 A 2 = ................. m 2l u1 = ...................................... m l u2 = ................. mr hy1 = A / l u = .......................... m r hy2 = ................. m(3) v * 1 = ...................................... m/s v * 2 = ................. m/sQ * 1 = v . A = .......................... m 3 /s Q * 2 = ................. m 3 /s(4) ∆Q 1 = Q soll - Q * = .................. m 3 /s ∆Q 2 = ................. m 3 /s(5) h 1 = h 1* .QQ ∗ = ................ mh 2 = 1,00 m genau!5-4