PART 12 Aquifer pumping tests - Dr. M. Zreda - University of Arizona

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Aquifer pumping tests 100 Case 2: No-flow (barrier) boundary (need zero gradient at boundary) We replace the barrier with an image pumping well (pumping at the same rate as the real pumping well). Because we have two pumping wells, they produce big drawdown. Will never reach steady state. Drawdown is calculated by superposition: s r s i Q = --------- ln--------------- 2.25Tt 4πT 2 S Q. How to demonstrate that this is a no-flow boundary? r r Q = --------- ln 2.25Tt --------------- 4πT 2 S r i Q s --------- 2.25Tt = ln--------------- 2πT rrr iS A. Derive an expression for gradient and show that the gradient in the direction normal to the boundary is zero at the boundary. Hydrogeology, 431/531 - University of Arizona - Fall 2007 Dr. Marek Zreda Qr real well (discharge) rr M ri Qi = Qr image well (discharge)
Aquifer pumping tests 101 Effects of boundaries on Theis and Jacob plots log drawdown drawdown ideal Jacob response Impermeable boundary log time log time impermeable boundary (slope is doubled) Ideal type curve Recharge boundary recharge boundary Hydrogeology, 431/531 - University of Arizona - Fall 2007 Dr. Marek Zreda
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PART 12 Aquifer pumping tests - Dr. M. Zreda - University of Arizona

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