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POSITIVE OPERATORS

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1.2. Extensions of Positive Operators 25<br />

Theorem 1.27. Let E and F be Riesz spaces with F Dedekind complete.<br />

If G is a Riesz subspace of E and T : G → F is a positive operator, then the<br />

following statements are equivalent.<br />

(1) T extends to a positive operator from E to F .<br />

(2) T extends to an order bounded operator from E to F .<br />

(3) There exists a monotone sublinear mapping p: E → F satisfying<br />

T (x) ≤ p(x) for all x ∈ G.<br />

Proof. (1) =⇒ (2) Obvious.<br />

(2) =⇒ (3) Let S ∈Lb(E,F) satisfyS(x) =T (x) for all x ∈ G. Then<br />

the mapping p: E → F defined by p(x) =|S|(x + ) is monotone, sublinear<br />

and satisfies<br />

T (x) ≤ T (x + )=S(x + ) ≤|S|(x + )=p(x)<br />

for all x ∈ G.<br />

(3) =⇒ (1) Let p: E → F be a monotone sublinear mapping satisfying<br />

T (x) ≤ p(x) for all x ∈ G. Then the formula q(x) = p(x + ) defines a<br />

sublinear mapping from E to F such that<br />

T (x) ≤ T (x + ) ≤ p(x + )=q(x)<br />

holds for all x ∈ G. Thus, by the Hahn–Banach Extension Theorem 1.25<br />

there exists an extension R ∈L(E,F) ofT satisfying R(x) ≤ q(x) for all<br />

x ∈ E. In particular, if x ∈ E + , then the relation<br />

−R(x) =R(−x) ≤ q(−x) =p (−x) + = p(0) = 0<br />

implies R(x) ≥ 0. That is, R is a positive linear extension of T to all of E,<br />

and the proof is finished.<br />

A subset A of a Riesz space is called solid whenever |x| ≤|y| and y ∈ A<br />

imply x ∈ A. A solid vector subspace of a Riesz space is referred to as<br />

an ideal. From the lattice identity x ∨ y = 1<br />

2 (x + y + |x − y|), it follows<br />

immediately that every ideal is a Riesz subspace.<br />

The next result deals with restrictions of positive operators to ideals.<br />

Theorem 1.28. If T : E → F is a positive operator between two Riesz<br />

spaces with F Dedekind complete, then for every ideal A of E the formula<br />

TA(x) =sup T (y): y ∈ A and 0 ≤ y ≤ x , x ∈ E + ,<br />

defines a positive operator from E to F . Moreover, we have:<br />

(a) 0 ≤ TA ≤ T .<br />

(b) TA = T on A and TA =0on A d .<br />

(c) If B is another ideal with A ⊆ B, then TA ≤ TB holds.

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