structure factors for polymer systems - NIST Center for Neutron ...
structure factors for polymer systems - NIST Center for Neutron ...
structure factors for polymer systems - NIST Center for Neutron ...
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0 ⎡ U1<br />
+ u + W11v1n<br />
1(<br />
Q)<br />
+ W12v<br />
2n<br />
2 ( Q)<br />
⎤<br />
v1<br />
n1<br />
( Q)<br />
= −S11(<br />
Q)<br />
⎢<br />
⎥ (38a)<br />
⎣<br />
k BT<br />
⎦<br />
v<br />
2<br />
n<br />
2<br />
( Q)<br />
= −S<br />
0<br />
22<br />
v1 1<br />
2 2<br />
⎡ U 2 + u + W21v1n<br />
1(<br />
Q)<br />
+ W<br />
( Q)<br />
⎢<br />
⎣<br />
k BT<br />
10<br />
22<br />
v<br />
2<br />
n<br />
2<br />
( Q)<br />
⎤<br />
⎥ (38b)<br />
⎦<br />
n ( Q)<br />
+ v n ( Q)<br />
= 0 . (38c)<br />
The last equation represents the incompressibility constraint. The non-interacting or<br />
“bare” <strong>structure</strong> <strong>factors</strong> S ( Q)<br />
0<br />
11 and S ( Q)<br />
0<br />
22 have been defined. These equations have<br />
assumed that no co<strong>polymer</strong>s are present in the homogeneous mixture; i.e., that<br />
0<br />
0<br />
S ( Q)<br />
= S ( Q)<br />
= 0 .<br />
12<br />
21<br />
In order to solve the set of linear equations, we extract the perturbing potential u from the<br />
second equation and substitute it into the first equation to obtain:<br />
0 ⎡U<br />
1 − U 2<br />
⎤<br />
1 n1<br />
( Q)<br />
= −S11(<br />
Q)<br />
⎢ + v11(<br />
Q)<br />
n ( Q)<br />
⎥ . (39)<br />
⎣ k BT<br />
⎦<br />
v 1<br />
This applies along with the following equation representing the response of the fully<br />
interacting system:<br />
⎡U 1 − U 2 ⎤<br />
v1<br />
n1<br />
( Q)<br />
= −S11(<br />
Q)<br />
⎢ ⎥ . (40)<br />
⎣ k BT<br />
⎦<br />
The factor v11(Q) and the Flory-Huggins interaction parameter χ12 are defined as:<br />
v<br />
χ<br />
11<br />
12<br />
( Q)<br />
1<br />
2χ<br />
12<br />
= −<br />
(41)<br />
0<br />
S22<br />
( Q)<br />
v 0<br />
W12<br />
⎛ W11<br />
+ W<br />
= − ⎜<br />
k BT<br />
⎝ 2k<br />
BT<br />
22<br />
Here v0 is a reference volume (often taken to be v 0 = v1v<br />
2 ).<br />
⎟ ⎞<br />
.<br />
⎠<br />
The RPA result <strong>for</strong> a homogeneous binary blend mixture follows:<br />
1 1 1 2χ<br />
S ( Q)<br />
11<br />
12<br />
= + −<br />
(42)<br />
0<br />
0<br />
S11(Q)<br />
S22<br />
(Q) v 0