Bounded Linear Operators on a Hilbert Space
Bounded Linear Operators on a Hilbert Space
Bounded Linear Operators on a Hilbert Space
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imaginary terms vanish, and we find that<br />
Self-adjoint and unitary operators 199<br />
|〈y, Ax〉| 2 = 1<br />
|〈x + y, A(x + y)〉 − 〈x − y, A(x − y)〉|2<br />
16<br />
≤ 1<br />
16 α2 (x + y 2 + x − y 2 ) 2<br />
= 1<br />
4 α2 (x 2 + y 2 ) 2 ,<br />
where we have used the definiti<strong>on</strong> of α and the parallelogram law. Using this result<br />
in (8.14), we c<strong>on</strong>clude that A ≤ α. <br />
As a corollary, we have the following result.<br />
Corollary 8.27 If A is a bounded operator <strong>on</strong> a <strong>Hilbert</strong> space then A ∗ A = A 2 .<br />
If A is self-adjoint, then A 2 = A 2 .<br />
Proof. The definiti<strong>on</strong> of A, and an applicati<strong>on</strong> Lemma 8.26 to the self-adjoint<br />
operator A ∗ A, imply that<br />
A 2 = sup |〈Ax, Ax〉| = sup |〈x, A<br />
x=1<br />
x=1<br />
∗ Ax〉| = A ∗ A.<br />
Hence, if A is self-adjoint, then A 2 = A 2 . <br />
Next, we define orthog<strong>on</strong>al or unitary operators, <strong>on</strong> real or complex spaces,<br />
respectively.<br />
Definiti<strong>on</strong> 8.28 A linear map U : H1 → H2 between real or complex <strong>Hilbert</strong><br />
spaces H1 and H2 is said to be orthog<strong>on</strong>al or unitary, respectively, if it is invertible<br />
and if<br />
〈Ux, Uy〉H2 = 〈x, y〉H1<br />
for all x, y ∈ H1.<br />
Two <strong>Hilbert</strong> spaces H1 and H2 are isomorphic as <strong>Hilbert</strong> spaces if there is a unitary<br />
linear map between them.<br />
Thus, a unitary operator is <strong>on</strong>e-to-<strong>on</strong>e and <strong>on</strong>to, and preserves the inner product.<br />
A map U : H → H is unitary if and <strong>on</strong>ly if U ∗ U = UU ∗ = I.<br />
Example 8.29 An n × n real matrix Q is orthog<strong>on</strong>al if Q T = Q −1 . An n × n<br />
complex matrix U is unitary if U ∗ = U −1 .<br />
Example 8.30 If A is a bounded self-adjoint operator, then<br />
e iA ∞ 1<br />
=<br />
n! (iA)n<br />
is unitary, since<br />
n=0<br />
e iA ∗ = e −iA = e iA −1 .