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Handbook of Civil Engineering Calculations

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FIGURE 34<br />

AERIAL PHOTOGRAMMETRY<br />

which is angle oLK1. Then d a. Let H flying height above sea level in meters,<br />

and dangle <strong>of</strong> dip in minutes. Then d1.775 2 H,<br />

Eq. a. This relationship is based<br />

on the mean radius <strong>of</strong> the earth, and it includes allowance for atmospheric refraction.<br />

From Fig. 34a, tan oK2/f, Eq. b. Then d 1.775 2 2925 96.0, or d 1°36.<br />

Also, tan 86.85/152.7 0.5688, giving 29°38. Thus, 1°36 29°38 <br />

31°14. From Fig. 34a, oK1 f tan , or oK1 152.7(0.6064) 92.60 mm. This dimension<br />

serves to establish the true horizon.<br />

2. Write the equation for the scale <strong>of</strong> a constant-scale line<br />

Since the optical axis is inclined, the scale S <strong>of</strong> the photograph is constant only along a<br />

line that is normal to the principal line, and so such a line is called a constant-scale line.<br />

As we shall find, every constant-scale line has a unique value <strong>of</strong> S.<br />

Refer to Fig. 35, where A is a point on the ground and a is its image. Line AQ is normal<br />

to the principal plane, Q lies in that plane, and q is the image <strong>of</strong> Q. Line Rq is a horizontal<br />

line in the principal plane. If the terrain is truly level and curvature <strong>of</strong> the earth may<br />

be disregarded, the vertical projection <strong>of</strong> the distance from A to L is H. Let e distance in<br />

photograph from true horizon to line qa. Along this line, S qa/QA Lq/LQ LR/LN.<br />

But LR e cos and LN H. Thus, S (e cos )/H, Eq. c.<br />

5.49

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