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Drawing of rods, wires and tubes

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Example: Determine the draw stress to produce a 20%<br />

reduction in a 10-mm stainless steel wire. The flow stress is<br />

given by σσσσ o = 1300εεεε 0.30 (MPa). The die angle is 12o <strong>and</strong> µ µ µ µ = 0.09.<br />

B<br />

From Eq.5<br />

From Eq.9<br />

= µ cotα<br />

=<br />

( 0.<br />

09)<br />

cot<br />

1 1<br />

ε1<br />

= ln = ln =<br />

1−<br />

r 1−<br />

0.<br />

2<br />

_ n<br />

0<br />

Kε1<br />

1300(<br />

0.<br />

223)<br />

σ = =<br />

n + 1 1.<br />

30<br />

σ<br />

σ<br />

xa<br />

xa<br />

_<br />

= σ<br />

o<br />

6<br />

o<br />

0.<br />

223<br />

. 30<br />

=<br />

_ ⎛ + B ⎞<br />

⎡ ⎛<br />

= σ ⎜ ⎟⎢1<br />

−<br />

B ⎜<br />

⎝ ⎠⎢<br />

D<br />

⎣ ⎝<br />

0.<br />

8571<br />

= 637MPa<br />

Suranaree University <strong>of</strong> Technology Tapany Udomphol<br />

Jan-Mar 2007<br />

D<br />

D<br />

2<br />

Ab<br />

1.<br />

0<br />

ln ( 1+<br />

B)<br />

= 637ln<br />

2<br />

A<br />

0.<br />

8<br />

a<br />

b<br />

a<br />

= 10mm<br />

=<br />

D<br />

b<br />

( 1<br />

( 1.<br />

8571)<br />

− r)<br />

=<br />

2B<br />

1 Da<br />

⎞ ⎛ 1.<br />

8571⎞<br />

8571<br />

b<br />

⎟<br />

⎠<br />

⎤<br />

⎥ = 637⎜<br />

⎟<br />

⎥ ⎝ 0.<br />

8571<br />

⎦<br />

⎠<br />

10(<br />

0.<br />

8)<br />

= 527MPa<br />

= 8mm<br />

2×<br />

0.<br />

[ 1−<br />

0.<br />

8 ] = 438MPa<br />

~ 20% difference

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